how would u solve for t if t is on the exponent??
\[0.1 = 0.5e ^{-250t}\]
make ln. on both sides so what will get ?
no sorry first divide both sides by 0,5 so what will get ?
0,1 = 0,5e^-250t divide both sides by 0,5 and will get 0,1/0,5 = e^-250t but you know that e^-250t = 1/(e^250t) yes ?
0,1/0,5 = 0,2 0,2 = 1/e^250t multiply both sides by e^250t and will get 0,2*e^250t = 1 divide both sides by 0,2 e^250t = 1/0,2 e^250t = 5 make ln on both sides ln e^250t = ln5 250t ln e = ln5 250t = ln5 t = ln5/250
@Nnesha your opinion please ? ty.
why are we multiplying by `e^{-250t} `
not by -250t just by 250t bc. there is 250t in denominator
jeez i lost all the work ohh my lord gzzzz one misssssclick...
e^-250t = 1/e^250t yes bc. there is exponent with minus in front
\[\large\rm 0.1 =0.5 e^{-250t}\] like jhonny mentioned divide both sides by .5 \[\large\rm \frac{0.1}{0.5}=\frac{0.5}{0.5}e^{-250t}\] \[\large\rm 0.2 = e^{-250t}\] now take ln both sides
no we don't need to do that once we take ln e would cancel out left with ln(0.2)=-250t
and then simply solve for t :=))
so this mean that my above wrote work not is right ?
yes i think so i believe that step is not necessary we should not be care about negative exponent because we know the fact ln and e cancel each otherz out
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