@3mar sorry brother I was sleeping., Could you help me

Question

zarkam21 · Answer

attachment

3mar · Answer

Yes, Of course.
I will never hesitate to give a helping hand!

zarkam21 · Answer

So can we start

3mar · Answer

Yes, Let's do it!

3mar · Answer

I think we did it before, don't I?

zarkam21 · Answer

We started it but didn't finish so I just posted it again

3mar · Answer

OK.
Do you have the link of what I had explained or do it from scratch!

zarkam21 · Answer

Let me tag you

3mar · Answer

@zarkam21 Do you follow?

sunnnystrong · Answer

So:
$$\left( 3x-2 \right)^2=10$$

--> Solve for x

$$3x-2=\sqrt{10}$$
Step one: take the square root of both sides to undo the square
--->
Step 2: add 2 to both sides
$$3x=\sqrt{10}+2$$
-----> Step 3: divide both sides by 3
....
What is x?

3mar · Answer

Actually @sunnnystrong the right-hand side would be $\pm \sqrt{10}$

sunnnystrong · Answer

@3mar oops.. yes (:

than you would have 2 solutions (1 probably being extraneous)

3mar · Answer

and one more thing ... but keep in down low,,,
it is $(2x+3)^2$ not $(3x-2)^2$

sunnnystrong · Answer

oh yeah... well same process so whatever XD @3mar 
it's all math hahahah

zarkam21 · Answer

Well are my solutions correcT?

3mar · Answer

@zarkam21 I have mentioned the correct approach of the problem at the other link! http://openstudy.com/study#/updates/5848e397e4b0ff7d2a1c0533 So A and F are not correct!

3mar · Answer

so Do you still need help at this?

3mar · Answer

Let me know when you are back!

3mar · Answer

http://openstudy.com/study#/updates/5848e397e4b0ff7d2a1c0533 that is the original question!