A car is driven on a straight track such that its displacement from the starting point is given as x = t + 2t^2. What is the average velocity (average rate of change of displacement) of the car between t = 2s and t = 4s?
A. 13 m/s
B. 12 m/s
C. 10 m/s
D. 8 m/s

Question

3mar · Answer

Well, I am here.
That is what I mean!

3mar · Answer

@Pbonnette 
Any ideas?

3mar · Answer

Let me know when you are back!

pbonnette · Answer

No clue to be honest @3mar

3mar · Answer

what is the given function\equation?

pbonnette · Answer

x=t+t^2

3mar · Answer

Great!
What does that equation represent?

pbonnette · Answer

Displacement right?

3mar · Answer

It represents the relation between the distance(x) and time(t).
am I right?

$\LARGE x=2t^2+t$

3mar · Answer

again you are not here!!!!!!!!!!!!!!!! @Pbonnette

pbonnette · Answer

I think so

3mar · Answer

so,,,,
what is the rate of change of $x(t)$???

mathmale · Answer

@phonnette:  Please give 3mar the courtesy of sticking with this discussion until you are finished.  Thank you.  Mathmale, Moderator

pbonnette · Answer

I've been here @mathmale

3mar · Answer

Let's proceed @Photon336 , please!

pbonnette · Answer

I think it is, like I said I don't know this

3mar · Answer

The rate of change of the distance is the velocity
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