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jimthompson5910 (jim_thompson5910):
good, so 4 will be in front of the n
ie you'll have 4n and not 5n
OpenStudy (itrymath):
so C
jimthompson5910 (jim_thompson5910):
the answer is either 4n+1 or 4n-1
to figure out which it is, plug in any point you want and see which points are satisfied
jimthompson5910 (jim_thompson5910):
yes 4n+1
OpenStudy (itrymath):
+
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OpenStudy (itrymath):
YAY omg i didnt think of slope formula thanks alot!!! my finals are next week on Wednesday and i need all help i can get thanks but these are last 2 and then i have 1 more that i know answer too but not sure how to get it
jimthompson5910 (jim_thompson5910):
go ahead
OpenStudy (itrymath):
the second one is in the picture i already provided you with xD
jimthompson5910 (jim_thompson5910):
any ideas for that one? or are you stuck completely and haven't gotten started?
OpenStudy (itrymath):
no ideas @jim_thompson5910
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jimthompson5910 (jim_thompson5910):
have you heard of the Fibonacci sequence?
OpenStudy (itrymath):
Yes a little
OpenStudy (itrymath):
only the name tbh
jimthompson5910 (jim_thompson5910):
the sequence is generated by adding the previous two terms
eg: 2+3 = 5
3+5 = 8
5+8 = 13
etc
jimthompson5910 (jim_thompson5910):
in terms of fancy notation, this means
f(n) = f(n-1) + f(n-2)
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OpenStudy (itrymath):
okay @jim_thompson5910
OpenStudy (itrymath):
@jim_thompson5910
jimthompson5910 (jim_thompson5910):
where are you stuck? there's only one answer choice that fits that format
OpenStudy (itrymath):
yeah thats the thing i dont understand
OpenStudy (itrymath):
the second one
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jimthompson5910 (jim_thompson5910):
f(n) is the nth term
f(n-1) is the term just before the nth term
f(n-2) is the term just before the f(n-1) term
jimthompson5910 (jim_thompson5910):
adding the previous terms before the nth term means we add up f(n-1) and f(n-2) to get
f(n) = f(n-1) + f(n-2)
jimthompson5910 (jim_thompson5910):
which is exactly how the Fibonacci sequence is defined
OpenStudy (itrymath):
like thats it or is there more??
OpenStudy (itrymath):
@jim_thompson5910
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jimthompson5910 (jim_thompson5910):
that's all there is to it. As long as n > 2, the sequence holds up
OpenStudy (itrymath):
what if it was the other way around
n was less than 2? @
OpenStudy (itrymath):
@jim_thompson5910
jimthompson5910 (jim_thompson5910):
it wouldn't work because n = 1 leads to f(n-2) = f(1-2) = f(-1) which doesn't make much sense
f(-1) would refer to the negative first term, which doesn't exist
OpenStudy (itrymath):
okay thanks !! so much i know i tagged you probably like 50 times today annoying the crap out of you but i have 1 more thing!
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OpenStudy (itrymath):
do you want new post or this is fine?
jimthompson5910 (jim_thompson5910):
either is fine
OpenStudy (itrymath):
OpenStudy (itrymath):
the answer i picked is correct but i found it on google and not sure how they got that answer
jimthompson5910 (jim_thompson5910):
you are correct
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jimthompson5910 (jim_thompson5910):
you can plug in each point into that equation to check
y = 4(2)^x
8 = 4(2)^1 ... plug in (x,y) = (1,8)
8 = 4(2)
8 = 8 ... works
y = 4(2)^x
64 = 4(2)^4 ... plug in (x,y) = (4,64)
64 = 4(16)
64 = 64 ... works
OpenStudy (itrymath):
wow that simple thanks !!!
OpenStudy (itrymath):
wish i could givve more medals :)
jimthompson5910 (jim_thompson5910):
I'm glad it's clicking now
OpenStudy (itrymath):
okay thats it for today will you be on tomorrow ?
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