Question

16?

Answer 1

oh ok now it is different, now you actually have to solve it

Answer 2

Oh okay

Answer 3

takes a few steps, number one, add 1 to both sides, get \[x^2+8x=20\] then add 16 to both sides (like you said) get \[x^2+8x+16=36\]

Answer 4

the reason for adding 16 is that the left hand side is a "perfect square" it is \[(x+4)^2=36\]

Answer 5

now you can take the square root of both sides (carefully) and get \[x+4=-6, x+4=6\]

Answer 6

finally subtract 4 from both sides, get \[x=-1, x=2\] there are two answers

Answer 7

we can do another one if you like, they take a bit getting used to

Answer 8

so just choice A?

Answer 9

no dear, there are two answer, \(x=2\) and \(x=-10\)

Answer 10

actually i may have some more problems like these so I will get my practice that way ;p

Answer 11

ok post another if you want, we can work through it step by step