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Mathematics 8 Online
OpenStudy (firechild17):

Anyone good with Square roots?

OpenStudy (firechild17):

OpenStudy (mathmale):

Please post your question up front. Anyone who has the time and feels capable of answering you question will respond.

OpenStudy (mathmale):

What are the instructions for this problem?

OpenStudy (firechild17):

All it says is to simplify

OpenStudy (mathmale):

In this case that means you need to multiply the two radicals together. The first one is sqrt(5), which can be written in "fractional exponent form" as\[5^{\frac{ 1 }{ 2 }}\]

OpenStudy (firechild17):

oh ok and than how would we do the 2nd one?

OpenStudy (mathmale):

The second is \[\sqrt[3]{5}\] which can be re-written as \[5^{\frac{ 1 }{ 3 }}\]

OpenStudy (mathmale):

So, the problem you have posted can be re-written as \[5^{\frac{ 1 }{ 2 }}*5^{\frac{ 1 }{ 3}}\]

OpenStudy (firechild17):

so itd be 5 1/6?

OpenStudy (mathmale):

Here you have the same base in each factor: 5. Therefore, to find the single exponent of 5 that answers this question, you must ADD together the 2 exponents, (1/2) and (1/3). How would y ou do that? Be sure to consider using the LCD (lowest common denom.)

OpenStudy (mathmale):

Rule:\[a^ba^c=a ^{b+c}\]

OpenStudy (firechild17):

so thatd be 2/5

OpenStudy (mathmale):

Sorry, but no. the Lowest Common Denominator here is not 5; it is (2)(3)=6. Try again. Add\[\frac{ 1 }{ 2 }+\frac{ 1 }{ 3 }\]

OpenStudy (mathmale):

Make a note: "Review LCDs."

OpenStudy (firechild17):

okay... so it is 1/6?

OpenStudy (mathmale):

No. Before you can add (1/2) and (1/3), both fractions MUST be changed so that they have the same denominator. (1/2) becomes (?/6); (1/3) becomes (?/6)

OpenStudy (mathmale):

Rewrite (1/2) as (3/6). Where did that 3 come from?

OpenStudy (firechild17):

I dont know....I am confused

OpenStudy (mathmale):

I have been trying to review "lowest common denominator" with you. At this point it appears that you need a careful review of that topic. Do you have a textbook? If so, could you look up "lowest common denominator?"

OpenStudy (firechild17):

no

OpenStudy (mathmale):

You must add (1/2) to (1/3). The LCD is 6. We want to re-write (1/2) so that it has the denom. 6. To do that, multiply numerator (1) and denom (2) by 3. What does the resulting fraction look like?

OpenStudy (firechild17):

3/6....OHHHH

OpenStudy (mathmale):

Good. Convert (1/3) to (?/6), using the same method. Do not mult. numerator and den. by 3 this time; mult by ???

OpenStudy (firechild17):

6?

OpenStudy (firechild17):

@mathmale 6???

OpenStudy (firechild17):

wait...2 @mathmale

OpenStudy (firechild17):

1/6...

OpenStudy (mathmale):

Right: 2. Mult. numerator and den. of (1/3) by 2.

OpenStudy (firechild17):

so its 5 1/6

OpenStudy (mathmale):

No, not 1/6. You have to mult both 1 and 3 in (1/3) by 2. Try again.

OpenStudy (firechild17):

2/6 oops

OpenStudy (mathmale):

Please do that mult. now.

OpenStudy (mathmale):

All right now you have 2 fractions with the SAME denom. (6), so you can now easily combine them into 1 result. Add: (3/6)+(2/6)

OpenStudy (firechild17):

5/6?

OpenStudy (firechild17):

so it would be 5 5/6?

OpenStudy (mathmale):

How'd you get that? Demonstrate what you did. Add 3/6 and 2/6.

OpenStudy (mathmale):

Your result MUST be a fraction with the denom. 6.

OpenStudy (firechild17):

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