Question

calc help

Answer 1

Was a particular method required of you? i suspect you'll need to do LONG division, because x^2 + x -1 itself has two roots.

Answer 2

Sunnystrong, could you please set up long div. and get jonea started on it? Thanks.

Answer 3

@mathmale i can try XD haha

Answer 4

\[f(x)= \frac{ 6x^4-x^{3}-x^2+9x-3 }{ x^2+x-1 }\]

Answer 5

Okay so:

Answer 6

@18jonea yes lol bear with me XD

Answer 7

@rishavraj
thank you hahaha too many different drawings... but basically:

you divide the first polynomial by the first term than multiply that term by the polynomial you're dividing by --> & so forth

Answer 8

http://www.sosmath.com/algebra/factor/fac01/fac01.html

Here is a howto

Answer 9

@18jonea I dont think :\
can u show ur solution

Answer 10

Well.. I haven't checked it but let me see.

Answer 11

@sunnnystrong lol ... bt u r good at tht :P

Answer 12

show ur work

Answer 13

@18jonea
Yep. I just did it out on paper and I got the same (:

Answer 14

Good job!!

Answer 15

yeah sure i'll try my best XD

Answer 16

Work -->

Basically you will be dividing the leading coefficient of the divisor (x^2) by the leading term in the dividend (6x^4)

From there --> you will multiply the quotient by the dividend (6x^2)(x^2+x-1) and writing it underneath the dividend (lining up the exponents that are alike)

Answer 17

@sunnnystrong good job :)

Answer 18

So: my first step was to
1.) Divide 6x^4/x^2 (and I got 6x^2) [See how I wrote it in the quotient)
2.) Next I multiplied (6x^2)(x^2+x-1) & I got 6x^4+6x^3-6x^2

Answer 19

See how I wrote that in the dividend --> lining up a like exponents

Now: you will subtract these (note that the leading dividend of the highest degree cancels out)

Answer 20

@18jonea wht u think ...wht value would u multiply with x^2 to get 6x^4 .....
so it would be x^2 * (6x^2) = 6x^4

Answer 21

Hmm.. ? I can write it out step by step if you want XD (would take another minute or two)

Answer 22

yep i would be honored to! :D

Answer 23

@18jonea here u go

Answer 24

u know we can write
\[\frac{ a + b }{ c }~=~\frac{ a }{ c } +\frac{ b }{ c }\]

Answer 25

@18jonea the last step

Answer 26

@18jonea
So here are my steps :D
I think you may need to zoom in to read but I tried to be as thorough as possible. It is essentially the same process throughout until you get to the remainder

Answer 27

NP Always my pleasure :D