Question

What is the average rate of change of the function below on the interval from x = 0 to x = 2?

http://prntscr.com/dhkmh0

Answer 1

D?

Answer 2

average rate of change given two x-values A and B:\[ROC=\frac{f(b)-f(a)}{b-a}\]

Answer 3

here we are given A=0, B=2, and \(f(x)=250(0.5)^x\)
therefore...\[\Large{ROC=\frac{f(2)-f(0)}{2-0}=\frac{250(0.25)^2-250(0.25)^0}{2}}\]

Answer 4

simplified further...\[\frac{0.0625-250(1)}{2}\]

Answer 5

I assume it's B then?

Answer 6

oops... put 0.25 instead of 0.5 it seems

Answer 7

ok so it is \[\frac{250(0.5)^2-250(0.5)^0}{2-0}=\frac{250(0.25)-250(1)}{2}\]

Answer 8

So D?

Answer 9

\[\cancel{\large{\checkmark}}\]no. sorry

Answer 10

http://www.wolframalpha.com/input/?i=(250(0.25)-250)%2F2

Answer 11

A?

Answer 12

yes

Answer 13

Thank you.

Answer 14

\[\large{\color{green}{\checkmark}}\]