Question

Math question please help

Answer 1

@@retirEEd @mathmale @Seratul

Answer 2

@retirEEd

Answer 3

If you have a fractional exponent, the denominator of the exponent becomes the root, and the numerator becomes an exponent INSIDE the root.
Example:\[\LARGE{x^{\frac{a}{b}}\rightarrow\sqrt[b]{x^{a}}}\]

Answer 4

Excuse the LaTeX glitch ^^;

Now on to part two. Area of a rectangle is length times width, \(l\times w\). Here you are given length \(l=3\) and width \(w=\sqrt{3}\).

Answer 5

\[\sqrt[3]{8}\]

Answer 6

or \[\sqrt[3]{8}^{1}\]

Answer 7

Plugging into the Area formula: \(l\times w=3\times\sqrt{3}\)
Now \(\sqrt{3}\approx1.732050807568877293527446341505872366942805253810380628055...\)
As you can see, \(\sqrt{3}\) yields an EXTREMELY long decimal, which doesn't seem to end. That means it's an irrational number.

Answer 8

And anything multiplied by an irrational number will still get you an irrational number (i.e. \(18\times\infty\) is not going to get you a rational result, since \(\infty\) is an irrational value), so your area is going to be an irrational value.

Answer 9

You got part 1 correct :-) good job \(\checkmark\)

Answer 10

okay yay!

Answer 11

how do i write it down on paper?

Answer 12

Which part?

Answer 13

part 1

Answer 14

\(\LARGE{x^{\frac{a}{b}}\rightarrow\sqrt[b]{x^a}}~therefore~\LARGE{8^{\frac{1}{3}}\rightarrow\sqrt[3]{8^{1}}}~or~\Large{\sqrt[3]{8}}\)

Answer 15

@kittiwitti1,\(\ \infty \) is not rational, nor irrational... It is a concept; an idea. It has no 'numerical' value to be defined as irrational.

Answer 16

Oh, I see. Thank you for the correction @tHe_FiZiCx99
It appears that I made an incorrect example for irrational numbers then.

Answer 17

mathlete agains't mathlete ooo

Answer 18

wait wa

Answer 19

seems right

Answer 20

No, he is correct haha

Answer 21

In combination with my other account, I have enough for Honorary. Though, it lacks a point.

Answer 22

wait so whats the problem?

Answer 23

\(\infty\) isn't rational nor irrational lol

Answer 24

well i get that but its clearly asking us which one is it

Answer 25

so what do i write for 2 (paper wise) to get all credits ?

Answer 26

okay

Answer 27

It's not rational because isn't rational, and nothing multiplied by an irrational number will get you a rational one

Answer 28

\[\sqrt{3}\]

Answer 29

yes \(\checkmark\) good job

Answer 30

I reckon it asks for you to solve for the area and deduce whether it is rational or irrational, irrespective of a general rule.

Answer 31

I suppose. I don't know what the parameters are for proving the rationality of the area.

Answer 32

in any case @ItryMath the area in "decimal form" would be \(3\sqrt{3}\approx5.196152422706631880582339024517617100828415761431141884167...\) thus, irrational number.

Answer 33

No idea what you screenshotted.

Answer 34

scroll up

Answer 35

It's not there.

Answer 36

oh lmao

Answer 37

(;

Answer 38

thanks a bunch !!! i do have 4 more mind sticking around in my new post?

Answer 39

My laptop is dying and I should be doing my own math xD
but sure !

Answer 40

i mean if not then its fine im sure there is others that can help

Answer 41

I will try my best, but I'll tell you when I have to go :-P