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Mathematics 10 Online
OpenStudy (nesha97):

how do i calculate this

OpenStudy (nesha97):

\[8^{2/3}\]

OpenStudy (astrophysics):

Think of it as \[\huge (8^2)^{1/3}\] where \[\huge x^{1/3} = \sqrt[3]{x}\]

OpenStudy (tkhunny):

Take your pick: \(8^{2/3} = \left(\sqrt[3]{8}\right)^{2} = \sqrt[3]{8^{2}}\)

OpenStudy (nesha97):

\[\sqrt[3]{8{^{2}}}\] \[\sqrt[3]{64}\] \[= 4\] is this right???

OpenStudy (astrophysics):

yeah :)

OpenStudy (tkhunny):

That's fine. With a little experience, you can pick the EASY way IF there is one. Rather than going up to 64 and than down to 4 You may wish to go down to 2 and then up to 4.

OpenStudy (mathmale):

Illustration: 8 = 2^3. Therefore, \[8^{\frac{ 2 }{ 3 }}=(2^3)^{\frac{ 2 }{ 3 }}.\]

OpenStudy (mathmale):

Can you now simplify the right side of this equation? Hint: mult (2/3) by 3.

OpenStudy (tkhunny):

As always, we see that unique answers don't care how you find them. :-)

OpenStudy (nesha97):

Thank you

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