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Chemistry 18 Online
OpenStudy (quizletisdown):

1.A sample of gold (Au) has a mass of 35.12 g. a.Calculate the number of moles of gold (Au) in the sample and record inTable 1. Show your work. b.Calculate the number of atoms of gold (Au) in the sample and recordin Table 1. Show your work.

OpenStudy (quizletisdown):

2.A sample of table sugar (sucrose, C12H 22 O 11 ) has a mass of 1.202 g. a.Calculate the number of moles of C 12H 22 O 11 contained in the sample and record in Table 1. Show your work. b.Calculate the moles of each element in C12 H 22 O 11 and record in Table1.Show your work. c.Calculate the number of atoms of each type in C12 H 22 O 11 and record

OpenStudy (sunnnystrong):

1a.) Gold (Au) has a mass of 35.12 g. *Calculate the number of moles of gold (Au) in the sample: Recall that: Gold has a Molar Mass of: 197g/mol |dw:1481574061263:dw|

OpenStudy (sunnnystrong):

2a.) *Calculate the number of atoms in the sample --> Recall that: 6.022x10^23 atoms in one mole |dw:1481574163879:dw|

OpenStudy (sunnnystrong):

2.) C12H22O11 has a mass of 1.202 g. Recall that C12H22O11 has a MM of = 342g/mol Calculate the number of moles of C12H22O11 contained in the sample Calculate the moles of each element in C12H22O11 in sample Calculate the number of atoms of each type in C12H22O11 |dw:1481574391437:dw|

OpenStudy (sunnnystrong):

|dw:1481574663528:dw|

OpenStudy (sunnnystrong):

For the last part: recall that there are 6.022*10^23 atoms in one mole --> so: 0.04214 Moles Carbon ( 6.022*10^23)= 2.538 * 10^22 Atoms Carbon 0.07726 Moles Hydrogen ( 6.022*10^23)= 4.653 * 10^22 Atoms Hydrogen 0.03863 Moles Oxygen ( 6.022*10^23)= 2.326 * 10^22 Atoms Oxygen

OpenStudy (quizletisdown):

Thank you so much @sunnnystrong

OpenStudy (sunnnystrong):

NP :D Always happy to help!

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