Verify that the function g(x)= 3x/x+7 satisfies the hypothesis of the Mean Value Theorem on the interval [-1,2]. Then find all the numbers c that satisfy the conclusion of MVT.
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OpenStudy (royalranger):
Do you know what the Mean value theorem states?
OpenStudy (hdrager):
yeah but idk how to apply
OpenStudy (royalranger):
is this function continuous at every point of the closed interval [-1,2]?
OpenStudy (hdrager):
everywhere except x=-7
OpenStudy (hdrager):
there's a hole there
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OpenStudy (hdrager):
oh so it is continuous on the interval
OpenStudy (royalranger):
So it is continuous on the interval [-1,2]. Which means it is differentiable on (-1,2). So find the derivavtive of the function.
OpenStudy (royalranger):
derivative*
OpenStudy (hdrager):
would the derivative just be 3?
OpenStudy (royalranger):
Is this your function?
\[\frac{ 3x }{ x+7 }\]
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OpenStudy (hdrager):
yes
OpenStudy (royalranger):
Have you learned the quotient rule yet?
OpenStudy (hdrager):
yeah
OpenStudy (hdrager):
ooooh oops
OpenStudy (royalranger):
I suggest you do it by hand to practice, but if you are already proficient in calculating the derivative, this could save time. Plus it shows the steps.
http://www.derivative-calculator.net/
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OpenStudy (hdrager):
\[\frac{ 21 }{ x^2+14x+49 }\]
OpenStudy (hdrager):
i tried it by hand
OpenStudy (royalranger):
Plug your function into the website i linked above, it will show you all the steps.
OpenStudy (hdrager):
i got it right
OpenStudy (hdrager):
they just didn't factor the denomiator
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OpenStudy (hdrager):
so what do I do next
OpenStudy (royalranger):
So now that you have that. Find:
\[\frac{ f(b)- f(a) }{ b-a }\]
OpenStudy (hdrager):
what was the point in taking the derivative of the original function then?
OpenStudy (royalranger):
Because after you find the value of
\[\frac{ f(b)-f(a) }{ b-a }\]
you will set that equal to the derivative and solve for x.
OpenStudy (hdrager):
also i got 15/6
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OpenStudy (hdrager):
so then I set 15/6 = to the derivative?
OpenStudy (royalranger):
yep
OpenStudy (hdrager):
ahh okay I'm confused on how to solve here
OpenStudy (hdrager):
for x
OpenStudy (royalranger):
you could multiply both sides by 1/21 to get rid of the 21 in the numerator.
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OpenStudy (hdrager):
okay so then I have (x+7)^2=15/126
OpenStudy (hdrager):
I unfactored it bc it seemed easier
OpenStudy (hdrager):
oops i messed up
OpenStudy (hdrager):
it would = 315/6
OpenStudy (hdrager):
then what should I do?
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OpenStudy (royalranger):
move the fraction other side so your function is equal to zero.
OpenStudy (hdrager):
okay then what
OpenStudy (royalranger):
use the quadratic equation to find x
OpenStudy (hdrager):
wait so i would be using x^2+14x-3.5 for the quadratic formula?
OpenStudy (hdrager):
i just want to make sure before I go at it
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OpenStudy (hdrager):
or should I stick with fractions?
OpenStudy (royalranger):
Alright so this whole time i have just been trusting that you have done all of the steps correctly without actually doing all of the work.
OpenStudy (royalranger):
i just did:
\[\frac{ f(b)-f(a) }{ b-a }\]
and i got 1/9
OpenStudy (hdrager):
wait how
OpenStudy (royalranger):
do you know what f(b) - f(a) means?
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OpenStudy (hdrager):
yeah you plug in the points from the given interval