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Mathematics 7 Online
OpenStudy (texmechanica):

Compute the perimeter of the rectangle using the distance formula. (round to the nearest integer) https://gyazo.com/e5b372412e70e08e03189628d77049e6 A) 22 B) 23 C) 38 D) 45

satellite73 (satellite73):

what a pain you have to identify three points one the rectangle i got \((3,8)\)for one of them |dw:1481590475031:dw|

OpenStudy (texmechanica):

Bottom angle is (8,3)

OpenStudy (texmechanica):

The one to the right is (11,6)

satellite73 (satellite73):

ok that is enough

satellite73 (satellite73):

|dw:1481590651488:dw|

satellite73 (satellite73):

do you know how to find the distance between \((3,8)\) and \((8,3)\)?

OpenStudy (texmechanica):

No.

satellite73 (satellite73):

you can use the distance formula, or just think

satellite73 (satellite73):

distance formula is \[\sqrt{x_2-x_1)^2+(y_2-y_1)^2}\]so for \[(8,3,), (3,8)\] it would be \[\sqrt{8-3)^2+(3-8)^2}=\sqrt{5^2+5^2}=\sqrt{50}\]

satellite73 (satellite73):

try it with \[(8,3),(11,6)\]

OpenStudy (texmechanica):

Working it now

OpenStudy (texmechanica):

I may have screwed it up.

OpenStudy (texmechanica):

It's 38.

OpenStudy (texmechanica):

Right?

satellite73 (satellite73):

hold on, got logged out

satellite73 (satellite73):

\[11-8=?\]

satellite73 (satellite73):

it is definitely not 38

OpenStudy (texmechanica):

Oh it's 23.

satellite73 (satellite73):

you mean the final answer? yes, that is what i got

satellite73 (satellite73):

i mean actually i got \[2(\sqrt{50}+\sqrt{18})\] but it rounded to 23

OpenStudy (texmechanica):

Right, thanks for the help.

satellite73 (satellite73):

yw

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