Compute the perimeter of the rectangle using the distance formula. (round to the nearest integer)
https://gyazo.com/e5b372412e70e08e03189628d77049e6
A) 22
B) 23
C) 38
D) 45
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satellite73 (satellite73):
what a pain
you have to identify three points one the rectangle i got \((3,8)\)for one of them |dw:1481590475031:dw|
OpenStudy (texmechanica):
Bottom angle is (8,3)
OpenStudy (texmechanica):
The one to the right is (11,6)
satellite73 (satellite73):
ok that is enough
satellite73 (satellite73):
|dw:1481590651488:dw|
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satellite73 (satellite73):
do you know how to find the distance between \((3,8)\) and \((8,3)\)?
OpenStudy (texmechanica):
No.
satellite73 (satellite73):
you can use the distance formula, or just think
satellite73 (satellite73):
distance formula is \[\sqrt{x_2-x_1)^2+(y_2-y_1)^2}\]so for \[(8,3,), (3,8)\] it would be \[\sqrt{8-3)^2+(3-8)^2}=\sqrt{5^2+5^2}=\sqrt{50}\]
satellite73 (satellite73):
try it with \[(8,3),(11,6)\]
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OpenStudy (texmechanica):
Working it now
OpenStudy (texmechanica):
I may have screwed it up.
OpenStudy (texmechanica):
It's 38.
OpenStudy (texmechanica):
Right?
satellite73 (satellite73):
hold on, got logged out
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satellite73 (satellite73):
\[11-8=?\]
satellite73 (satellite73):
it is definitely not 38
OpenStudy (texmechanica):
Oh it's 23.
satellite73 (satellite73):
you mean the final answer? yes, that is what i got
satellite73 (satellite73):
i mean actually i got \[2(\sqrt{50}+\sqrt{18})\] but it rounded to 23
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