Question

can somebody explain how you differentiate this type of function?

Answer 1

\[f(x)=\frac{ 1 }{ x-3 }\]

Answer 2

Quotient Rule

Answer 3

Granted there are multiple ways, but generally you can just use the quotient rule.

Answer 4

\[f(x)=(x-3)^{-1}\]

Answer 5

\[\frac{ d }{ dx }x^n=nx ^{n-1}\]\[f(x)=\left( x-3 \right)^{-1}\]
\[f \prime \left( x \right)=-1(x-3)^{-2}=\frac{ -1 }{ \left( x-3 \right)^2 }\]

Answer 6

What @sshayer said :D

Answer 7

Or just give them the answer lol

Answer 8

\[or~\frac{ d }{ dx }(\frac{ u }{ v })=\frac{ vu \prime-uv \prime }{ v^2 }\]
where u and v are functions of x

Answer 9

\[\frac{ d }{ dx }\left( c \right)=0\]
where c is a constant.

Answer 10

also what @royalranger said XD

Answer 11

generally we use power rule.

Answer 12

okay I get it now, I just wasn't sure how to change the fraction