Im not sure if the answer i got are right someone help The nth term of a geometric sequence is given by an= 1/4^(4)n-1 . Write the first five terms of this sequence.
a1=1/4 a2=1 a3=4 a4=16 I feel like i got these wrong can someone help
and a5=64
Hmmm... Well \[a _{n}=\frac{ 1 }{ 4 }^{4n-1}\] is that correct @Isabelle99 ?
or is it....... \[a ^{n}=\frac{ 1 }{ 4 }(4)^{n-1}\] because that'd make more sense
If so: the sequence is \[\frac{ 1 }{ 4 }, 1, 4, 16, 64\] & you're right :D
thanks
NP :D Always happy to help out
I didn't even see you previous answer yes thats what i meant to put
Okay.. well than it's different
If \[a _{n}=\frac{ 1 }{ 4 }^{4n-1}\] The sequence is: \[\frac{ 1 }{ 4 }^3,\frac{ 1 }{ 4 }^7,\frac{ 1 }{ 4 }^{11},\frac{ 1 }{ 4 }^{15},\frac{ 1 }{ 4 }^{19}...\]
no it was the first one you said
my bad
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