The function f is defined on the domain [-4,4] by
\(f(x)=x+5,-4\le~x\le-2\)
\(f(x)=x^{2}+2,-2<x\le2\)
and \(f(x)=-x+7,2<~x\le4\)
Sketch the graph of f.
@kittybasil
The latex is not working properly. I cannot understand your question :-|
but i can c d latex... xD
sometimes it takes time to load @aravindg
Let's graph each thing piece by piece this is f(x) = x + 5 for −4 ≤ x ≤ −2 notice how because there are "or equal to" things, the end point dots are fully black |dw:1481656070473:dw|
now let's graph f(x) = x^2 + 2 for -2 < x ≤ 2 now notice how it is an open dot at (-2, 6) I also included the points I used to reference what this graph looks like |dw:1481656309112:dw|
and lastly, the graph of f(x) = -x + 7 for 2 < x ≤ 4 same idea |dw:1481656578388:dw|
@MARC If you got confused on any part of this, feel free to ask ^_^ I'm sorry for replying so late (which is why I tried including all the necessary steps) here is a fun fact - because of the way they limited the domains of each function, this graph as a whole DOES pass the vertical line test :)
Thanks for the explanation.Really helps me a lot. @Angle ^_^
To anyone who says they can't see the LaTeX:

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