Question

Ada says that the length of diagonal SQ is two times the length of diagonal OM.

Is Ada correct? Justify your answer and show all your work. Your work should state the theorem you used to find the lengths of the diagonals.

Answer 1

http://marion.flvs.net/webdav/assessment_images/educator_mjprealgebra_v16/03_09_part2_g2_q3.jpg

Answer 2

I cannot access the picture

Answer 3

Assuming that LMNO is a square
we can try to work this problem out by using the Pythagorean theorem in order to find the length of SQ and the length of OM

Answer 4

the Pythagorean theorem is \(a^2 + b^2 = c^2 \)
where a and b are sides of the rectangles (or "legs")
and c is the "hypotenuse" or SQ

because of this, we can say that
\(14^2 + 7^2 = (SQ)^2\)
and try to solve for or estimate SQ

Answer 5

meanwhile

Answer 6

using the same formula I described above...
\(7^2 + 7^2 = (OM)^2\)

This should be enough information to get you to your answer :)

If you still need help, please do reply @Naruko885 ^_^ I would really appreciate hearing where you're having trouble so I can help you better :3

Answer 7

I think I get what your saying but can you help me like plug in the numbers in the right spots? thanks.

Answer 8

I already plugged in all the numbers for you ;)

\(14^2 + 7^2 = (SQ)^2\)
and
\(7^2 + 7^2 = (OM)^2 \)

all you have to do is solve for SQ and OM

Answer 9

SQ 98 and OM 49?

Answer 10

oh wait I think I did it wrong.

Answer 11

wait did I do it wrong, im confused??

Answer 12

mhmm something might be wrong

\(14^2\) = 196
\(7^2\) = 49
196 + 49 = 245

Answer 13

then the square root of 245 is about 15.6

Answer 14

ohhh I accidently x not + sorry. I get it now.

Answer 15

thank you so much!