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Mathematics 9 Online
OpenStudy (pj754):

help! Can some explain why P(X≥1)=1-P(X=0)

OpenStudy (irishboy123):

if that's true, you mean that: \(P(X≥1)=1-P(X=0)\) And that \(1= - P(X≥1)- P(X=0)\) None of which makes sense :((

OpenStudy (holsteremission):

Looks like \(X\) is a random variable with a discrete distribution. If it's a proper distribution, then \(\sum\limits_x\mathbb P(X=x)=1\). The support appears to be non-negative integers, so the sum translates to \[\sum_{x=0}^\infty\mathbb P(X=x)=1\iff \mathbb P(X\ge0)=1\] We could take one term out of the sum, then we have \[\mathbb P(X=0)+\sum_{x=1}^\infty\mathbb P(X=x)=1\iff \mathbb P(X\ge1)=1-\mathbb P(X=0)\]

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