Question

can someone explain this to me

Answer 1

Show two ways of finding y if \[y=\log _{4}64\]
Explain please....

Answer 2

You can rewrite this as
64=4^y

Answer 3

And then you can just solve. Y has to be 3.

Answer 4

For example,
\(y=\log_5(125)=\log_5(5^3)=3\times \log_5(5)=3\times 1 = 3\)

Answer 5

i knew that way its just i can't think of another way to write that

Answer 6

note that \(64=4^3\), so if you just apply the rules of logarithms, you can get the answer in a split second.

Answer 7

i think i understand it

Answer 8

Yeah, and you don't need to re-write it as an exponential.
(You would if you had something like \(2=\log_5(y)\) ...)

Answer 9

\[y=\log _{4}(64)=\log _{4}(4^{3})=3 *\log _{3}(4)=3\]

Answer 10

like that??

Answer 11

You take the exponent inside the log outside

Answer 12

Fix your second to last step.

Answer 13

what do you mean??