Question

Please help

Answer 1

Let logb A=5, logb C=7, logb D=2
What is the value of logb
\[\frac{ A ^{5}C ^{2} }{ D ^{6} }\]

Answer 2

First tel me - Do you know that

log (a*b) = log a + log b

and also

log a^x = x log a

Answer 3

yes i understand that

Answer 4

OK

No we can alos write your expression as
\[A ^{5} \times C ^{2} \times D ^{-6}\]

OK?

Answer 5

(hint)
log (a*b*c) = log a + log b + log c

Answer 6

so using that expression first and THEN
log a^x = x log a

you should see the answer...

Answer 7

Wait what do i do with with the exponents

Answer 8

log a^x = x log a

Answer 9

\[\log _{b} A ^{^{n}} = n \log _{b} A\]

Answer 10

(just be careful with the negative exponent)

Answer 11

so when i add them i add the log of a,b, and c?? or do i add them all up and then fing the log of them??

Answer 12

it asks you to find the log of the expression

so add the log of all the components log (a*b*c) = log a + log b + log c

THen use log a^x = x log a to sort out the exponents

Then put you numbers in to get the solution

:

Answer 13

You said you understood the two log rules that I put in my first reply.

Just apply the two rules one after teh other as I described above

Answer 14

i got 8.98 i think i did something way wrong

Answer 15

I went wrong somewhere...I need help

Answer 16

\[\log _{b} \frac{ A ^{5}C ^{2} }{ D ^{6} } = \log _{b} A ^{5} \times \log _{b} C ^{2} - \log _{b} D ^{6}\]
\[5 \log _{b}A + 2 \log _{b} C - 6 \log _{b} D\]
\[5 \times 5 + 2 \times7 - 6\times2\]
\[25+14-12 = 27\]

Answer 17

Thank you

Answer 18

your welcome, glad to help

Answer 19

@Nesha97
Did you REALLY learn anything other than 'the answer is 27'

@hafeda
People learn far better by DOING than by having the work done for them

Answer 20

i actually did learn something. The way i had done it was way wrong and now i see where i went wrong. I thought i was suppose to use those as exponents but now i see that i wasn't, its really just confusing doing it the way u did it