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Mathematics 15 Online
OpenStudy (starfruityum):

Which of the following is a step in simplifying the expression

OpenStudy (starfruityum):

OpenStudy (starfruityum):

@AloneS

OpenStudy (tkhunny):

\(\left(\dfrac{a}{b}\right)^{-c} = \left(\dfrac{b}{a}\right)^{c}\)

OpenStudy (starfruityum):

OpenStudy (starfruityum):

I dont really understand this D:

OpenStudy (tkhunny):

I don't care what the answers are. Please work it out. I gave you a hint. Do that, first.

OpenStudy (starfruityum):

So. I would switch the denominator and the numerator and make the -4 positive 4 @tkhunny ?

OpenStudy (tkhunny):

That's all that rule does. Hopefully, that should simplify your life a little. Then, we can do step #2

OpenStudy (tkhunny):

Then this rule: \(\left(\dfrac{a}{b}\right)^{c} = \dfrac{a^{\;c}}{b^{\;c}}\)

OpenStudy (starfruityum):

im still confused.. How do i use that rule with the expression i have? @tkhunny

OpenStudy (tkhunny):

You have a numerator and a denominator. Put the exponent in each of them. You may wish to first enclose each in a new set of parentheses.

OpenStudy (starfruityum):

Is it A @tkhunny?

OpenStudy (tkhunny):

I haven't worked it out. I'm waiting to see your work. All the exponents should be multiples of 4. Don't forget this rules: \(\left(a^{b}\right)^{c} = a^{b\cdot c}\ne a^{b+c}\)

OpenStudy (starfruityum):

So B? If all the exponents should be multiples of 4, then B is the only option with multiples of 4 as exponents

OpenStudy (tkhunny):

:-)

OpenStudy (starfruityum):

Thanks :D

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