Is this correct
Hi again you know you can check the asnwers yourself right? on the computer
oh btw i think this is wrong `
This is a different problem, I understand the concept for those problems now
\[ax^2+bx+c=0\\ 4x^2+5x+4=0\\ a=4,b=5,c=4\]
compute \[b^2-4ac\] which in this case is \[5^2-4\times 4\times 4\]
i get \[-39\] how about you ?
Yup just checked on my calculator
I got -39 as well
ok so it is negative, that is the important part that means there are two COMPLEX solutions
So it wouldn't be "two negative" It would be complex?
if you use the quadratic formula you would get \[x=\frac{-5\pm\sqrt{-39}}{8}\]with a negative number under the square root symbol, meaning two complex solutions
no not "two negative" two complex
\[b^2-4ac\]is called the discriminant for \(ax^2+bx+c=0\) if it is negative, two complex solutions
Oh okay, I think I'm understanding now
yay \[\large \color\green\heartsuit\]
So because of the negative number under the square root symbol. it would be two complex solutions
yes, that is right
Thanks beautiful
yw darling
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