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Mathematics 17 Online
zarkam21 (zarkam21):

Is this correct

zarkam21 (zarkam21):

OpenStudy (misty1212):

Hi again you know you can check the asnwers yourself right? on the computer

OpenStudy (misty1212):

oh btw i think this is wrong `

zarkam21 (zarkam21):

This is a different problem, I understand the concept for those problems now

OpenStudy (misty1212):

\[ax^2+bx+c=0\\ 4x^2+5x+4=0\\ a=4,b=5,c=4\]

OpenStudy (misty1212):

compute \[b^2-4ac\] which in this case is \[5^2-4\times 4\times 4\]

OpenStudy (misty1212):

i get \[-39\] how about you ?

zarkam21 (zarkam21):

Yup just checked on my calculator

zarkam21 (zarkam21):

I got -39 as well

OpenStudy (misty1212):

ok so it is negative, that is the important part that means there are two COMPLEX solutions

zarkam21 (zarkam21):

So it wouldn't be "two negative" It would be complex?

OpenStudy (misty1212):

if you use the quadratic formula you would get \[x=\frac{-5\pm\sqrt{-39}}{8}\]with a negative number under the square root symbol, meaning two complex solutions

OpenStudy (misty1212):

no not "two negative" two complex

OpenStudy (misty1212):

\[b^2-4ac\]is called the discriminant for \(ax^2+bx+c=0\) if it is negative, two complex solutions

zarkam21 (zarkam21):

Oh okay, I think I'm understanding now

OpenStudy (misty1212):

yay \[\large \color\green\heartsuit\]

zarkam21 (zarkam21):

So because of the negative number under the square root symbol. it would be two complex solutions

OpenStudy (misty1212):

yes, that is right

zarkam21 (zarkam21):

Thanks beautiful

OpenStudy (misty1212):

yw darling

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