Question

Could someone help me find the inflection point of this graph?

Answer 1

The graph is e^-x^2. I thought the inflection point was (1/sqrt(2), 1/sqrt(e)) and then (-1/sqrt(2), 1/sqrt(e)), but that wasn't correction

Answer 2

HI!!

Answer 3

\[e^{-x^2}\]right ?

Answer 4

Yes! And hello!

Answer 5

definitely has two

Answer 6

first derivative i get \[-2xe^{-x^2}\] via chain rule

Answer 7

Right

Answer 8

second derivative \[ e^{-x^2} (4 x^2 - 2)\]

Answer 9

set it equal to zero, means set \[4x^2-2=0\] solve for \(x\)

Answer 10

sqrt(1/2)?

Answer 11

looks like i am getting the same thing you are

Answer 12

\[x=\pm\frac{1}{\sqrt2}\]

Answer 13

maybe they want you to write it as \(\frac{\sqrt2}{2}\)

Answer 14

it is right, maybe the syntax is wrong for Alex, hard to know

Answer 15

It didn't like sqrt2/2 either, I'm not sure what to do

Answer 16

here, even the wolf agrees
http://www.wolframalpha.com/input/?i=inflection+points+e%5E(-x%5E2)

Answer 17

I figured it out...it hated that I put parentheses haha

Answer 18

make sure to put \[-\frac{\sqrt2}{2}\] for the first one, since it wants the negative one first

Answer 19

oooh

Answer 20

oh will...

Answer 21

Thank you so much! I really appreciate it

Answer 22

welcome, but you did all the work!\[\color\magenta\heartsuit\]