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Mathematics 11 Online
OpenStudy (steve816):

Which strategy shall I use to evaluate this integral?

OpenStudy (steve816):

\[\large \int\limits_{}^{}\sec^3x~dx\]

imqwerty (imqwerty):

Hint:Write sec^3x like this-> (1+tan^2x)secx

OpenStudy (steve816):

I don't see anything I can substitute there after writing it like that.

OpenStudy (welshfella):

or you could use a reduction formula

OpenStudy (steve816):

Hmm, what is the reduction formula??

OpenStudy (holsteremission):

Try integrating by parts with \[\begin{matrix} u=\sec x&&&\mathrm dv=\sec^2x\,\mathrm dx\\[1ex] \mathrm du=\sec x\tan x\,\mathrm dx&&&v=\tan x \end{matrix}\]Then \[\begin{align*} \int\sec^3x\,\mathrm dx&=\sec x\tan x-\int\sec x\tan^2x\,\mathrm dx\\[1ex] &=\sec x\tan x-\int\sec x(\sec^2x-1)\,\mathrm dx\\[1ex] 2\int\sec^3x\,\mathrm dx&=\sec x\tan x+\int\sec x\,\mathrm dx \end{align*}\](This is the result of the reduction formula which is derived from integrating by parts.)

OpenStudy (zarkon):

\[\sec(x)=\sec(x)\frac{\sec(x)+\tan(x)}{\sec(x)+\tan(x)}=\frac{\sec^2(x)+\sec(x)\tan(x)}{\sec(x)+\tan(x)}\]

OpenStudy (steve816):

Wow, I would never have guessed that this was a integration by parts problem. But that makes it so much easier.

OpenStudy (steve816):

Thank you guys for the help.

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