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OpenStudy (seratul):
\[\log \sqrt[3]{M^4N}\]
OpenStudy (zrock):
sorry dude still in 8th grade wish i could help
OpenStudy (zrock):
also i have no idea what this means
OpenStudy (seratul):
It's okay. :P
OpenStudy (seratul):
@zepdrix
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OpenStudy (eliesaab):
\[
\sqrt[3] {A B}=A^{1/3} B^{1/3}
\]
OpenStudy (eliesaab):
\[
\sqrt[3] {A^m b^n}=A^{m/3}B^{n/3}
\]
OpenStudy (seratul):
Alright
So we can have logM^(4/3)+logN^(1/3)
OpenStudy (seratul):
What would I do after that?
OpenStudy (eliesaab):
Sorry, Let me do it in an easier way
\[
\ln(\sqrt[p]{A^kB^s})=\frac 1 p \ln(A^k B^s)=\frac 1 p \left( k \ln(A)+ s \ln(B) \right)
\]
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OpenStudy (eliesaab):
Use the above formula and you will be done
OpenStudy (eliesaab):
Did you get it?
OpenStudy (seratul):
What about the B^8??
OpenStudy (eliesaab):
It is B^s the letter s
OpenStudy (eliesaab):
In your case
\[
\ln \sqrt[3]{M^4N}
\] and the general case is
\[
\ln(\sqrt[p]{A^kB^s})=\frac 1 p \ln(A^k B^s)=\frac 1 p \left( k \ln(A)+ s \ln(B) \right)
\]
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