Quadrilateral ABCD is located at A(−2, 2), B(−2, 4), C(2, 4), and D(2, 2). The quadrilateral is then transformed using the rule (x − 3, y + 4) to form the image A'B'C'D'. What are the new coordinates of A', B', C', and D'? Describe what characteristics you would find if the corresponding vertices were connected with line segments.
So a point P(m,n) will be transformed in P'(m-3, n+4) So apply the above to each point and you will be done
i said A' : -5, 6 B': -5, 8 C' -5. 8 D: -5, 6 prob wrong
A(−2, 2), B(−2, 4), C(2, 4), and D(2, 2) A'=(-2-3, 2+4)=(-5,6) B'=(-5,8) C'=(2-3,4+4)=(-1,8) D'=(2-3,2+4)=(-1,6)
Did you see your mistakes
oh yes sorry about that
Fine, one learns from his/her mistakes
:) very true. Do you think you can help with part 2 of the question?
Give it s try and tell me what you get
Try to graph the points A', B', C' and D'
where
On the x,y plane
ok one sec
So what can you conclude?
What is the quadrilateral A'B'C'D'?
Is it a square?
it is a rectangle
Great, you got ti
thank you so much for your help!
No Problems
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