Find the average mean? http://prnt.sc/dk06yu
@3mar i know how to find the average (mean) but im not sure how on this one because the results never match up with the answer options.
What do you think?
2 - 2.5 was the closest number i was getting
@3mar i added all the numbers (equaling 1) and found the average (divided by 5) and the result was 0.2. Then i found the average of just the ones who HAD siblings and left out 0. But it still wasnt right
"Then i found the average of just the ones who HAD siblings and left out 0." What so you mean by that?
What do x and p(x) stand for?
i didnt include the decimal of those who did not have siblings
good idea multiply and add
multiply what?
the probabilities by the numbers
\[1\times 0.6+2\times 0.05+3\times 0.15+4\times 0.1\]
@satellite73 1.55 - would it mean B or C?
dunno i cannot read the mind of the person who made the question, but given the \(4+\) at the end of the table, i would round up
i would not bet more than $7 on that answer though
Does it tell you anything that the greatest probability by far is 0.6? Under what number (of siblings) do you find that? Notice the prob. to the left of 0.6 is 0.1 and that to the right of 0.6 is 0.05. What do you suppose the graph of these probabilities would look like? Would it be possible to infer the mean of all this data just by looking at the given table or the graph that you would draw?
i dont know, ill try
@mathmale i did but i dont think it means anyhting
is it not clear how to do this?
if not that is fine, tell me and i will show you how to do it
i found the average, though i guess not the right way because i cant get the correct result. So yeah if you could thatd be great
ok lets imagine that there are 100 students in the class
There is a simple procedure for finding the average value; it consists of multiplying each possible sibling count (0, 1, 2, .. ) by the probability that appears underneath each such count. Then you add the products together. Unfortunately, that 4+ creates a problem, since that 4+ could represent 4, 5, 6, 7, ... On the other hand... the value 1 appears many times more often than does any other value. Seems to me that that tells us immediately that the average number of siblings is 1 or very close to 1.
i messed up it is \[1\\ 0.6\] so \(60\%\) of the students have on sibling
what is \(60\%\) of 100? (don't think too hard)
3/5 = 0.6
yeah i was asking what \(60\%\) of 100 was, not what .6 is as a decimal
i see the problem i just computed it and got 1.55 too, which is not an answer choice so you have to choose between 1.5 and 2
i.e. round up or down like i said, i would round up but that is just a guess
exactly, thats where im at
thank you @satellite73 and @mathmale
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