Question

Determine algebraically whether the function is even, odd, or neither even nor odd.

f(x) = 3x2 - 1

Answer 1

I think its even but im not sure

Answer 2

May I help?

Answer 3

ok thanks

Answer 4

yes please

Answer 5

Thank you.
With my pleasure!

You are in the right track:
If it's even, then f(-x) = f(x)
If it's odd then f(-x) = -f(x)

Answer 6

so you do 3(-x)^2 -1 ?

Answer 7

\[\Large f(x) = 3x^2 - 1\]
\[\Large f(\color{red}{-x}) = 3(\color{red}{-x})^2 - 1=-3x^2-1\neq f(x)\neq -f(x)\]

Answer 8

Does it make sense for you now?

Answer 9

Thank you for the medal!
That is so kind of you!
@satellite73

Answer 10

yes so its odd because its not the same as it was before

Answer 11

If it's even, then f(-x) = f(x)
If it's odd then f(-x) = -f(x)

If f(-x) is neither equal to f(x) nor -f(x), so it is ....?

Answer 12

neither?

Answer 13

Yes ....
\[\Huge\color{MediumSpringGreen }\checkmark\]
You hit the right target!

Answer 14

thank you!

Answer 15

Wait Wait Wait Wait Wait

Answer 16

@nani200

Answer 17

yes?

Answer 18

Why did you let me do this wrong and you did not even comment?

\[\Large f(\color{red}{-x}) = 3(\color{red}{-x})^2 - 1=-3x^2-1\]

Answer 19

i didnt notice

Answer 20

what's wrong about it?

Answer 21

@3mar i dont see anything wrong with it

Answer 22

\[\Large f(\color{red}{-x}) = 3(\color{red}{-x})^2 - 1=3x^2-1=f(x)\]