Between 1970 and 2000, the population of a city decreased by approximately 2% each year. In 1970 there were 600,000 people. What is the population in 2000?

Question

tkhunny · Answer

1970 600000
1971 600000 * 1.02
1972 600000 * 1.02^2
1973 600000 * 1.02^3
1973 600000 * 1.02^4

Etc.

sunnnystrong · Answer

Recall that:
$$A=(A_{0})b^n$$
A= amount
Ao= initial
b=decay factor (1- percent of decay)
n=time
Between 1970 and 2000, the population of a city decreased by approximately 2% each year. In 1970 there were 600,000 people. What is the population in 2000?

If the percent of decay = .02 --> than the decay factor is .98
If the initial amount of people = 600,000
Than the equation is:

$$A=600,000(.98)^n$$
What is n @ 30 years ?

tkhunny · Answer

Whoops.  Decreasing, not increasing.  Listen to Sunny.

mathmale · Answer

@Krausesav:  Please respond in some way when other users are trying to help you.  If someone has helped you, please thank that person, and then close your post.

krausesav · Answer

Okay, thank you so much sunny I think I got it!