Write a direct variation equation that relates x to y. Then solve. Show both the equation and the solution. If y = 8 when x = 4, find y when x = 5.
@Awolflover1 @518nad
y = kx That's all there is to it. Go!
\(\bf \begin{array}{cccccclllll} \textit{something}&&\textit{varies directly to}&&\textit{something else}\\ \quad \\ \textit{something}&=&{\color{brown}{ \textit{some value}}}&\cdot &\textit{something else}\\ \quad \\ y&=&{\color{brown}{ n}}&\cdot&x \\\hline\\ && y={\color{brown}{ n }}x \end{array} \\ \quad \\ \textit{so, when }y=8\quad x=4\implies 8={\color{brown}{ n}}4\implies {\color{brown}{ n}}=?\)
once you find "n" or "k" as tkhunny used, that is, the "factor of variation", then you'll know what "y" is when x = 5, because y = n x, so, if you know "n", "n times 5" will be y
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