Question

Help?

http://prntscr.com/dkm37h

Answer 1

For a vertical hyperbola:

Answer 2

For question 8:
Given the vertices of the hyperbola: (-5,0) & (5,0)
Recall that the vertices give coordinates (h +/- a, k)
Since we now that the hyperbola is centered at the origin... than h,k = 0
So: a=5
Recall that the co-vertices give coordinates (h, b+/- k)
If the co-vertices are (0, 6) & (0,-6)
Than:
\[\frac{ (x)^2 }{ 5^2 }-\frac{ (y)^2 }{ 6^2 }=1\]
\[\frac{ (x)^2 }{ 25 }-\frac{ (y)^2 }{ 36 }=1\]

Answer 3

so the answer is D

Answer 4

yep for question 8. what do you think about question 9? @Theoneandonly

Answer 5

im guessing between A and D

Answer 6

@Theoneandonly
It's going to be a horizontal hyperbola.
Foci... give you length c (5)
Vertices... give you length a (4)
So yep it's D :D