Question

The polynomial given below has _____ root(s).2x2 + 2x + 4
A.one positive and one negative
B.two complex
C.two positive
D.two negative

Answer 1

First find the value of the discriminant b^2 - 4ac
can you do that/

Answer 2

No can you help me out more? whats a b and c?

Answer 3

a b and c sre the coefficients in the equation

ax^2 + bx + c = 0
so compare it with
2x^2 + 2x + 4 to get the values of a b and c for this equation.

Answer 4

compare term by term
we see that
a = 2
what is the value of b and c?

Answer 5

Wouldn't it be 2 also?

Answer 6

which one would be 2? b or c?

Answer 7

i think may be the first step factorize out the 2

Answer 8

yes You could do that

Answer 9

2(x^2 +x +2) =

Answer 10

and now the discriminant is less than zero so from what result that there are two complex roots

Answer 11

ahemm....just to clarify \(\bf
{\color{red}{ 2}} x^2{\color{blue}{ +2}} x{\color{purple}{ +4}}\to
\begin{cases}
{\color{red}{ a}}\\
{\color{blue}{ b}}\\
{\color{purple}{ c}}
\end{cases}\qquad
\begin{cases}
discriminant
\\\hline\\
{\color{blue}{ b}}^2-4{\color{red}{ a}}{\color{purple}{ c}}
\end{cases}\)

Answer 12

I think the poster is confused and has left ..

Answer 13

soooo megan98888... what did you get?

Answer 14

Given: y = 2x^2 + 2x + 4 compare this to the standard form of a quadratic:
y = ax^2 +bx +c

Just match up the coefficients. Yes, a=2. What are the values of coefficients b and c?