Check please? :) http://prntscr.com/dl3vig
@zepdrix :3
hmmm thought you were asking for the restaurant bill so I was going to hand you one plus 35% tips =)
Hahaha, I don't get you. :p So I'm correct? :P
so hmmmm what makes say hmmm \(\sqrt{6}\ and\ \sqrt{2}\) examples of 1) and 2) closed under addition anyway?
first off, what "closed under addition" mean anyway? they don't like being added, so they closed each other to that
bear in mind that \(\bf {\color{brown}{ \sqrt{2} }}\impliedby irrational \\ \quad \\ \sqrt{6}\implies \sqrt{3\cdot 2}\implies \sqrt{3}\cdot {\color{brown}{ \sqrt{2} }}\)
Sorry, I'm back now! Let me check. :)
Oh... So it's all of them got it :)
:O
zeppyyyyy lol i don't really have a clue But my teacher went over this before and she also had struggles haha
oh boy XD
hehehe hmm what does "closed under addition" mean though?
May I use google? :p
sure thing
So a set is closed under addition if the sum of any two elements in the set is also in the set. For example, the real numbers R have a standard binary operation called addition (the familiar one). Then the set of integers Z is closed under addition because the sum of any two integers is an integer.
nice paste jabez1777 oooook, what does that mean?
one would note that copy/paste simple means, "this is what I read verbatim" not "this is what I understand"
@jabez1777 anyhow, http://www.mathsisfun.com/sets/closure.html <-- this may help clearing out that some then you'll who may or may not be closed under addition keep in mind you're asked on "rational" numbers
Close under addition will mean that the sum of two numbers inside of a space belongs to the space itself.
Given two numbers in the form of a/b and c/d where a,b,c and d belong to R the sum a/b + c/d belongs to the rationals.
Okay now this is confusing the daylight out of me! hahahaha Let me try and understand it ugh lol
well ahemm.... closed under addition, as I understood from that article is two or more, items added, both items being of the same "GENRE', will yield a result of the same "GENRE" so, two integers will produce an integer result two rationals will produce a rational result bear in mind that \({\color{brown}{ \sqrt{2} }}\impliedby irrational \\ \quad \\ \sqrt{6}\implies \sqrt{3\cdot 2}\implies \sqrt{3}\cdot {\color{brown}{ \sqrt{2} }} \)
|dw:1482109984279:dw|This is the worst analogy ever, but I'm gonna go with it lol
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