Helpp please with: find the value of c that makes the polynomial a perfect square trinomial. x^2+8x+c
@zarkam21 it is the same process u did just right now
I understand but I usually get assistance =)
Because I am new to the process
DO the second term as follow : \[ \pm (\frac{ b }{ 2 } ) ^{2}\] it will be much better to do it first, u will learn more that way
so 8/2
(8/2)^2
yes
16?
yes now add 16 to both side of the equation , or add 16 and subtract 16
16x^2 +16+16?
\[x ^{2} + 8x +16 - 16\]
no, substitute 16 for 'c'
Oh okay I see what you did
now u have a complete square and of \[(x+4) ^{2} - 16 \]
Oh okay and then c would be 16?
hafeda, i think you are over solving the problem and yes, zarkam21, c would be 16 :D
and that is constant out the square is the "C" @chiunlee12 i just want her to understand the process, and same time that ask it differently
@zarkam21 yes c = 16
Would it be the same process for this
@hafeda Yeah, I understand what you tried to do there, and your explanation was great
Okay now that is almost the same as the first question
Wants a perfect square trinomial, a polynomial with 3 terms and factors like (a - b)^2 = (a - b)(a - b) = a^2 - 2ab + b^2 or (a + b)^2 = (a +b)(a + b) = a^2 + 2ab + b^2 notice the last term in these are squares, 2^2 ,3^2 , 4^2 , 6^2,.... x^2+8x+c to get an 8 in the middle from the sum of 2 *perfect square, you need to use 4 (x + 4)^2 = x^2 + 8x + 16
Okay and then we would continue to solve for b am I correct?
@3mar
3mar is here!
Yay =)
so? where did you reach?
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