Question

Help please with this 4 part question

Answer 1

Part1 Hint: the area is an example of the difference of 2 squares so you can use the identity

a^2 - b^2 = ( a + b)(a - b)

Answer 2

- this helps with Part 2 also!

Answer 3

Part 1 :- l = area / width = (36x^4 - 64x^2) / (6x^2 + 8x)

Answer 4

to solve this you can either use long division or factor the top by using the formukla for the difference of 2 squares then simplifying

Answer 5

What is the square root of 36x^4 and 64x^2?

Answer 6

My first post should have been a hint for Part 2 not part 1. Hope this hasn't confused you.

Answer 7

Are you still there?

Answer 8

Yes I am here

Answer 9

So Part 1 :- l = area / width = (36x^4 - 64x^2) / (6x^2 + 8x)

Answer 10

yes

Answer 11

and then for part 2?

Answer 12

What is 36x^4 - 64x^2 a Perfect Trinomial or the Difference of 2 Squares?

Answer 13

check out my earlier posts...

Answer 14

so 1675520

Answer 15

???? What is that the answer to?

Answer 16

Oh I'm sorry I was calculating 36x^4 - 64x^2 :/

Answer 17

Part 2 just asks you to state what is the description of the expresion 36x^4 - 63x^2 -
a perfect square trinomial or the Difference of 2 squares?

Answer 18

oh sorry sorry I got confused :/

Answer 19

you can give a numerical value to that because x is a variable

Answer 20

* can't

Answer 21

it would be difference of two squares right?

Answer 22

exactly

Answer 23

So part 3 is just basically solving?

Answer 24

Yes
now we can factor that
compare the following

a^2 - b^2 = ( a + b) (a - b)
36x^4 - 64x^2 = (6x^2 + 8x) ( )

Answer 25

What will go into the second parentheses?

Answer 26

Ote the square root of 36x^4 is 6x^2
and square root of 64x^2 is 8x

Answer 27

* Note

Answer 28

6x^2-8x?

Answer 29

YES

Answer 30

so l = area / width = (6x^2 + 8x (6x^2 - 8x) / 6x^2 + 8x) = 6x^2 - 8x

Answer 31

and this would still be part of part 3 right?