What is the average rate of change of the function f(x)=2(3)x from x = 2 to x = 4?
is the problem \(f(x)=2(3)^x\)?
Yes
next time, i suggest you write the problem as f(x) = 2(3)^x instead ^ denotes exponents when x=2 what is 2(3)^x =? when x=4 what is 2(3)^x=?
It would be \[f4=2(3)^{4}\], right?
f(4) yes
Just f(4)?
f(4) = 2(3)^4 the parenthesis is important now, when you punch the right side into a calculator, what value do you get?
\[f(4)=2(3)^{4}\]?
3^4 = 81 2*81 = ?
162
right, so when x=4, then f(4) =162
so when x=2, f(2) = ?
Ok, so should I just write 162 or actually write f(4)=162?
write f(4)=162, though thats not the answer
Okay so one question, how did we get 81?
oh, im guessing you're not familiar with powers if you have x*x*x*x*x its not fun to write out 5 x's so instead you represent it as \(x^5\)
Oh right, 3x3x3x3
so 3^4=\(=3^4=3*3*3*3=9*9=81\)
Okay understood now :)
ok, so the 2nd step, what is f(2)=? or f(x) when x=2?
So when 2 is X 2=4
2x2=4
why? the function f(x) = 2(3)^x what happened to the 3?
all you're doing is just replacing the x with 2
Oh
So 2 would either be f(2) or (3)^2
no... when you substitute 2 in, you get f(2) = 2(3)^2 cant separate/ignore the equal sign
f(2) = 2(3)^2 so what does 2(3)^2 =?
9?
3^2 = 9 so 2(3^2) = 2*9 = ?
18
ok so f(2) = 18 yes?
i mean ify ou want to show your steps, which teachers love looking at, you can write it f(2) =2(3)^2 = 18 or just break it up into 2 steps
So 18 is the answer?
f(2) = 2(3)^2 f(2)=18
And yea I would like to do that
no... what is your question asking? copy and paste it
What is the average rate of change of the function f(x)=2(3)x from x = 2 to x = 4?
??
ok, average rate of change it is the equivalent of saying , what is the slope?
between the two points x =2 and x=4
Isn't it 3?
That was wrong, wasn't it?
What is the avergae rate of change then?
Cuz I'm just lost
sorry, forgot i was still doing this do you remember what slope is? or what hte slope formula is ?
Slope is something is basically the term that happens evently, like how many gallons he/she used per mile. Sorry I'm not exactly a good explainer
or miles per gallon, this is a rate, similar to rate of change being asked in your problem but more generally, slope ona graph describes how steep the curve is
Oh
now, if you have 2 points, then if you remember the slope formula, \[m=\frac{y_2 - y_1}{x_2-x_1}\]
except this case, we have no y actually, you can consider f(x) as y so f(2) = y2 and f(4) = y1, x2= 2 and x1 =4
substitute that all in and tell me what m would be m is slope
oh uhh...
I'm sorry for giving a hard time, I'm not very sure
My mind is just so stupid when it comes to equation formulas
ok, that the information you already have , put it in terms of ordered pairs f(4) = 162 :: (4,162) f(2)= 18 :: ( 2, 18)
Ahh okay, that makes sence
does that make it a bit more clear? now, apply these points to the slope formula \[ m= \frac{y_1-y_2}{x_1-x_2}\]
the resulting value would be the slope aka rate of change
But how would I apply these numbers to the slope formula?
ordered pairs come in the form (x,y)
always
Is the answer 9?
I divided 162 by 18, and I just thought that it might be a way to solve it
doesnt matter which order you do the subtraction, as long as its in the same order top and bottom that sounds a bit low \[\frac{162-18}{4-2}\]
\[\frac{ 162-18 }{4-2}=\frac{18-162}{2-4}\]
So do I subtract those?
162- 18 =?
144
4-2=?
2
144/2=?
72
m= 72 now you understand how to find slope from 2 points?
or rate of change between 2 point?
Oh, lol math is such a Jerk XD and yes
math has an specific order in which to do things, this order is unchanging, as long as you understand the order, things really are not that hard though i do suggest you memorize the slope formula or basic theory on how you find slope from 2 points, you will probablly see it alot in the future, so better to learn it now rather than having to constantly relearn it over and over and over and over again
Okay, I've taken notes from this discussion
also, if you;re familiar with PEMDAS or BODMAS or BEDMAS fractions if you want to write it linearly are written [numerator]/[denominator]
Bodmas and Bedmas? Never heard of those
writing x1-x2/y1-y2 = \(x_1 -\frac{x2}{y1} -y2\)
in canada i think its Bedmas- bracket exponent etc.
Oh okay
some places call it bracket , order, and switch multiplicatio nadn division
all the same thing though, "order of operations"
lol I'll remember that
well, good luck with the rest
Thx so much, you were such a great help
and a study tip, while this website is still up, try to help people with their problem and explain how to get the answer (since last i heard its closing next year) try to understand the concept well enough that you are able to explain it other, a bit like reviewing the concept and they might ask you questions you mightve never thought of when initially learning
Will do, but I have to go right now
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