Ask your own question, for FREE!
Mathematics 15 Online
OpenStudy (uscrnamc):

please help will medal but dont give me a wrong answer so you can just get a medal

OpenStudy (uscrnamc):

OpenStudy (sooobored):

ok looking at g(x) lets make an assumption, that (-1,-1) is related to (0,1) from f(x) and that (0,1) is related to (1,3) from f(x)

OpenStudy (sooobored):

now, first, just looking at the (-1,-1) and (0,1) what transformation must you do in order to go from (0,1) to (-1,-1)?

OpenStudy (uscrnamc):

i dont know

OpenStudy (uscrnamc):

horizontal?

OpenStudy (sooobored):

well, if you have a starting point of (0,0) and you move horizontally 1 unit to the right, then the corresponding point would be (1,0) right?

OpenStudy (sooobored):

if you moved vertically 1 unit down from (0,0), then the corresponding point would be (0,-1) right?

OpenStudy (uscrnamc):

i guess

OpenStudy (sooobored):

ok, then if you want to go from (0,1) and want to go to (-1,-1), how many units horizontally and vertically do you need to go? if you cant do it in your head, i suggest drawing it

OpenStudy (sooobored):

and in which direction?

OpenStudy (uscrnamc):

i dont know 1 unit hor and 2 unit vert

OpenStudy (sooobored):

left or right, up or down?

OpenStudy (uscrnamc):

left 1 unit and down 2 units

OpenStudy (jdoe0001):

hmmmm ever got g(x) ?

OpenStudy (jdoe0001):

so... how's g(x) "shifted" from the original then?

OpenStudy (uscrnamc):

-1? @jdoe0001 if -1 would the equation for getting g(x) would my answer be g(x)=3x-1?

OpenStudy (jdoe0001):

hmmm how come is 3x -1? what shifts in it makes it so?

OpenStudy (uscrnamc):

idk i just gonna guess and submit my answer i just have been on this test for more than 2-3 hours thanks for the help

OpenStudy (uscrnamc):

eh i was close lmao THE RIGHT ANSWER is g(x) = (3)(^x+1)-2

OpenStudy (jdoe0001):

heehe

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!