Question

The vertices of a quadrilateral ABCD are A(−3, 4), B(−4, 1), C(−7, 2), and D(−7, 6). The vertices of another quadrilateral EFCD are E(−11, 4), F(−10, 1), C(−7, 2), and D(−7, 6). Which conclusion is true about the quadrilaterals?

Their corresponding diagonals are equal.
The measures of their corresponding angles are not identical.
The lengths of their corresponding sides are unequal.
Their shapes and sizes are not identical.

Answer 1

I say A. Agree? @3mar

Answer 2

Did you plot these?

Answer 3

yes and my answer i got is A

Answer 4

do u agree

Answer 5

How does they look like?

Answer 6

okay then heres the next Q and this will be the last since you have to go:

Answer 7

In a quadrilateral ABCD, the diagonals intersect at point T. Byron has used the Alternate Interior Angles Theorem to show that angle DAC is congruent to angle BCA and that angle BAC is congruent to DCA.

Which of the following can Byron use prove that side AD is equal to side BC?

AC ≅ AC
AC ≅ DB
DB ≅ DB
TB ≅ TD


I say its A

Answer 8

agree?

Answer 9

What about the first one?

Answer 10

you said u dont have time so i will just do this one for the last

Answer 11

I cant help with this just yet, im sorry @JULYAHX1

Answer 12

A: Their corresponding diagonals are equal.
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as they are congruent polygons

Answer 13

https://www.desmos.com/calculator/5nlnzbqezu

Answer 14

oh great! so i was correct thank you

Answer 15

Yes, as always

Answer 16

and the second question i am right as well?

Answer 17

seeing it

Answer 18

ok

Answer 19

It would be ASA postulate..
ok?

Answer 20

ok

Answer 21

So we got two congruent angles, still need the side between them,,
which is AC

Answer 22

so im correct yay lol XD