Shayna enlarged a square photo by adding 10 inches to each side so it could be seen on a large poster. The area of the enlarged photo is 256 square inches. In the equation (x + 10)2 = 256, x represents the side measure of the original square photo.
What is the question? Do you need to solve for x, the length of the side of the original photo?
\((x + 10)^2 = 256\) \((x + 10)(x + 10) = 256\) \(x^2 + 10x + 10x + 100 = 256\) \(x^2 + 20x + 100 = 256\) \(x^2 + 20x - 156 = 0\) \(x + 26)(x - 6) = 0\) \(x + 26 = 0\) or \(x - 6 = 0\) \(x = -26\) or \(x = 6\) Since a square cannot have a side measuring a negative number, we discard the solution x = -26. The answer is the original photo had a side of 6 inches. Check: Add 10 inches to a side of a square of 6 inches to get a side of 16 inches. A square with a side of 16 inches has area A = s^2 = (16 in.)^2 = 256 in.^2 Our answer is correct.
\[\left( x+10 \right)^2=256=\left( 16 \right)^2\] \[x+10=\pm 16\] \[either ~x+10=16,x=16-10=6\] or x+10=-16 x=-16-10=-26 (rejected) as side of square can not be negative.
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