Help please: attached
y-y1=m(x-x1) this is point slope form you need to know a point (x1,y1) and the slope m=(y2-y1)/(x2-x1), you need to know 2 points of the line for the slope, (x1,y1) and (x2,y2)
Point slope: \[y - y_1 = m(x-x_1)\] Slope Intercept form: y = mx + b
You are already given the slope and a point. Now just plug in the values for m, y1 and x1.
-5-y=-1/4(-6-x)
No, you plug in -5 for y1 and -6 for x1
y+5=-1/4(x+6)
Yes, now distribute -1/4
y+5=-1/4x-1.5
y=-1/4x-6.5
Ivonne, this problem is very, very similar to the one we did 40 minutes ago. The illustration gives you the slope of the line (m=-1/4) and one point (-6,-5) on that line. You are required to start with the point-slope form of the equation of a line (similar to last time). That point-slope form is y-k=m(x-h). Since the point is (-6,-5), h=-6 and k=-5; the slope is m=-1/4. Just substitute. Might be a good idea to take a few notes on each problem solution, to help you remember when you have to apply the same knowledge or methods to a new situation.
Thats it.
You end up with slope-intercept form, as required, after having started with the point-slope form.
@mathmale would this be the correct form?
You have arrived at y = -x/4 + 13/2, and want to know whether or not this is the correct form. To check this equation, go back and fetch the given point; it is (-6,-5). Substitute -5 for y in the above equation, and -5 for x. -5=-(-6)/4 + 13/2. You want to know whether this is true or not. Multiplying every term by 4 eliminates the fraction 1/4: -20=6+26 Does -20=32? Obviously not, so something is wrong here.
Ok
Look back to what we did earlier. YOU found that y+5=-1/4(x+6) Let's mult. both terms (there are only 2 terms at the moment) by -4 to eliminate the fraction (-1/4): -4y - 20 = x + 6. You must solve this for y to obtain an equation in slope-intercept form. Divide all terms by -4 now. y=??
-4y=x+26
y=x/-4 - 6
\[y=-\frac{ 1x }{ 4 }- 6\]
As before, you need to check your answer. To do this, determine whether or not the given point (-6,-5) satisfies YOUR latest equation. If it does, your answer is correct; otherwise your answer is not correct. Substitute -5 for y now, followed by subst. -6 for x. Is the resulting equation true?
i believe not
why
We will have to find out what went wrong as you went from one form (point-slope) to another form (slope-intercept). What was your very first answer (point-slope form)?
I dont know
I was asking you to go back and locate your own work. What I'm going to do now is to forget about the point-slope form and jump directly into slope-intercept form. Look at the given graph. The line goes thru which point? The line has what slope?:
-1/4
yes, and that line goes thru which given point?
given : (-6, -5)
Yes. Now we'll jump directly to slope-intercept form: y=mx+b. We know all of y, m and x, but don't know b yet. subst. -5 for y, -6 for x, and (-1/4) for m. Find b.
Reviewing your past work, it seems as tho you had the correct answer, except for the sign of 13/2. Almost finished with your latest calculations?
-13/2
Right. Slope is -1/4, y-intercept is -13/2. Equation is then y = (-1/4)x - 13/2. That's it.
would it be ok to put: \[y=-\frac{ 1x }{ 4 } - \frac{ 13 }{ 2 }\]
Yes. That's correct. But I still think you should check it once more. Does this line pass thru (-6,-5)? To check that, let x=-6 in your equation (above). Does the equation predict that =-5?
yes just double checked it
Then you have the correct equation. The only thing wrong with your previos result was that your sign for 13/2 was incorrect.
Thank you for the medal!
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