What is the volume of a spherical segment whose base has a height of 2 cm and the diameter of the sphere measures 6 cm... The answer says it's 28/3 *pi* cm^3 , but I didn't get that one... I need a guide, so I can even show my procedure
I need to apply this formula= \[V=\frac{ 2 }{ 3 }\pi*r ^{2}h-\frac{ 1 }{ 3 }\pi*R ^{2}\left( r-h \right)\]
@ShadowLegendX @TheSmartOne
@Shad0w
@skullpatrol
May I guide you?
of coursee you can @3mar
what is your advice?
@zepdrix
|dw:1482357672992:dw|
you got it.
take a look of my procedure...
did you see?
yes i have used the formula you gave. volume of sector of height 2=2/3 pi 3^2*2=36/3pi volume of cone =1/3 pi r^2 (R-h) =1/3 pi (sqrt 8)^2 (3-2)=8pi/3 then subtract. you need only volume ,no area.
we need volume of cap only.
radius of sphere 6/2=3 cm
that's right! however I took h= 1 cm because exercise says that base is above centre "O" a distance of 2 cm, so "h" is the height that starts from base until the top of the sphere
so, you say I should take as "h" value 2 cm instead of 1 cm right?
thanks @sshayer
Sorry, I was not here! but I think @sshayer did it very well... thanks to him
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