What is the volume of a spherical segment whose base has a height of 2 cm and the diameter of the sphere measures 6 cm... The answer says it's 28/3 *pi* cm^3 , but I didn't get that one... I need a guide, so I can even show my procedure
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OpenStudy (crisulcampo):
I need to apply this formula=
\[V=\frac{ 2 }{ 3 }\pi*r ^{2}h-\frac{ 1 }{ 3 }\pi*R ^{2}\left( r-h \right)\]
OpenStudy (crisulcampo):
OpenStudy (crisulcampo):
@ShadowLegendX @TheSmartOne
OpenStudy (crisulcampo):
@Shad0w
OpenStudy (crisulcampo):
@skullpatrol
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OpenStudy (3mar):
May I guide you?
OpenStudy (crisulcampo):
of coursee you can @3mar
OpenStudy (crisulcampo):
what is your advice?
OpenStudy (crisulcampo):
@zepdrix
OpenStudy (crisulcampo):
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OpenStudy (sshayer):
|dw:1482357672992:dw|
OpenStudy (sshayer):
you got it.
OpenStudy (crisulcampo):
take a look of my procedure...
OpenStudy (crisulcampo):
OpenStudy (crisulcampo):
did you see?
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OpenStudy (sshayer):
yes i have used the formula you gave.
volume of sector of height 2=2/3 pi 3^2*2=36/3pi
volume of cone =1/3 pi r^2 (R-h)
=1/3 pi (sqrt 8)^2 (3-2)=8pi/3
then subtract.
you need only volume ,no area.
OpenStudy (sshayer):
we need volume of cap only.
OpenStudy (sshayer):
radius of sphere 6/2=3 cm
OpenStudy (crisulcampo):
that's right! however I took h= 1 cm because exercise says that base is above centre "O" a distance of 2 cm, so "h" is the height that starts from base until the top of the sphere
OpenStudy (crisulcampo):
so, you say I should take as "h" value 2 cm instead of 1 cm right?
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OpenStudy (crisulcampo):
thanks @sshayer
OpenStudy (3mar):
Sorry, I was not here!
but I think @sshayer did it very well... thanks to him