Question

multiplication- (x^2+5x-14)(x/7)

Answer 1

.hmmmm
I see (x^2+5x-14)(x+7) not (x/7) though

but the multiplication is very straightforward
you can simply multiply "x" times the trinomial
then +7 times the same trinomial
and then add/subtract any like-terms

Answer 2

yes you are right i typed it wrong

Answer 3

could you work it out for me

Answer 4

well \(\bf \begin{array}{rllll}
x^2+5x-14
\\ \quad \\
\qquad \times \qquad x+7
\\\hline\\
\square ?+\square ?+\square ?\\
\square ?+\square ?+\square ?
\end{array}\)


there, just like any simple multiplication
do the "x" first, for the 1st line of results
do the "7" next, for the 2nd line of results
combine them

Answer 5

omg that helped so much

Answer 6

yw

Answer 7

would i do the same thing for addimg and subtraction

Answer 8

ahmm nope
adding and substraction are even simpler
all you have to do is remove the parentheses
and combine them

keeping in mind that, when a parentheses has a - is really a -1 or -1*
so (a+b) - (c+d) is really (a + b) -1 * (c + d)
which is (a + b) -c -d
or
a +b -c -d

so... in this case \(\bf (x^2+5x-14)-(x+7)\implies (x^2+5x-14)-1\cdot (x+7)
\\ \quad \\
(x^2+5x-14)-x-7\implies x^2+5x-14-x-7\)

Answer 9

oh wow