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Mathematics 14 Online
iwanttogotostanford:

help ASAP calculus question

iwanttogotostanford:

If h(x) = f[f(x)] use the table of values for f and f ′ to find the value of h ′(1). TABLE: x f(x) f'(x) 1 3 2 2 1 5 3 6 7

iwanttogotostanford:

@steve816

iwanttogotostanford:

someone please

iwanttogotostanford:

???

Ultrilliam:

@AMQ *cough cough*

AMQ:

and you think i know calculus?

Ultrilliam:

@Bob ??? x'D

AMQ:

thanks for the complement though ;)

Zarkon:

use the chain rule

Zarkon:

\[h'(x)=f'(f(x))f'(x)\] then evaluate at \(x=1\)

mathmale:

From the table, obtain the values of the following: f(1), f'(1), f'(3). Give this a try.

iwanttogotostanford:

@zarkon can you explain further please

iwanttogotostanford:

i seriously need help lmao

iwanttogotostanford:

@wo1f0mon

wo1f0mon:

umm i know how add and subtract

wo1f0mon:

so i dont know how do dis sorry!

mathmale:

Simply stated, you have to use the Chain Rule. Supposing that f(x) and g(x) are functions, h(x) = f ( g(x) ) is called a "composite function." The Chain Rule pertains to differentiating such a function. Here is the formula for this situation: h '(x) = f '( g(x) ) g '(x) In words: The derivative of h(x) is equal to the derivative of f with respect to g(x) TIMES the derivative of g(x) with respect to x. Now, in this case, you want the derivative of h(x) = f (f(x) ). We follow the same rule as above, exactly: h '(x) = f' ( f(x) ) * f '(x) Can you take the solution of this problem from here, or do you need and want further explanation? As one example, the value of f '(1) can be obtained from the given table and is 2.

mathmale:

Borrowed from Zardon: h'(x)=f'(f(x))f'(x) then evaluate at x=1 In other words: 1) Find the value of f '(1) from the table. It is 2. 2) Find the value of f (1) from the table. It is 3. 3) This 3 is the input to f '(x). Find the value of f '(3) from the table. It is 7. Now put this whole works together. What is the value of h(1)?

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