I hope question cove is smart enough to answer this: Why is the domain of tan( arcsin(x/2) ) equal to (-2,2) I know that the domain of arcsin(x/2) is (-2,2), I don't know why the tangent function didn't change it.
a few users are, but the aren't online at the moment :/
sigh....please don't make me go back to the other dumb sites
like what? brainly and pa? lol
Uhm, if mathmale or sat where on right now, they could help :(
*were also, @tranquility could possibly answer it :/
Wait, I have someone who might be able to help
Mathmale gives me PTSD
I'm talking to someone who is guiding me through how to answer this for you :)
The tangent function does change the domain. for the arcsin(x/2), the domain includes points -2 and 2. while when you include the tangent, those x=-2 and x=2 areas/lines become asymptotes and at no longer included
Oh.........RIGHT yes
but ask your boyfriend why the tangent doesn't change the (-2,2) into anything else, like why is it still 2.
First of it's a girl, and she is way older then me. and second, i'm asking her now.
Sorry for the long wait lol
it's not that it doesn't change the domain or range - the idea behind it does change the arcsin(x/2)'s domain of [-2,2] because of how the stuff in the parenthesis of arcsin is limited from -1 to 1 meanwhile, tan = opp/adj from arcsin(x/2) we get that opp=x and hyp=2 so from that we can get that adj=sqrt(4-x^2) so the tan(arcsin(x/2))=x/(sqrt(4-x^2)) and that is where that domain comes from
Yes - there are restrictions on the domain of the tangent because of the restrictions on the sine
I LOVE YOU ULTRILLIAM AND YOUR BOYFRIEND
I have more hope for qc now
it still isn't my boyfriend :| once again, its a girl. GIRL And i'm glad! :D Welcome aboard! ^_^
Is it a girlfriend? o;
That's why Aeon was created. cx
Oh boy, not at all Elsa lol
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