rootbeer003:
help
satellite73:
what?
rootbeer003:
I have a lot to do.
satellite73:
get busy
satellite73:
oh for gods sake cancel the \(x-4\) top and bottom c'mon
satellite73:
next ...
rootbeer003:
a
satellite73:
right
satellite73:
weird lookiing
satellite73:
does some answer look like \[q\neq -1,q\neq 8\]>
rootbeer003:
idk
satellite73:
cause that is what you get when you set \[q^2-7x-8=0\] and solve
satellite73:
your post just had a bunch of random question marks
rootbeer003:
ik
rootbeer003:
thats what it shows
satellite73:
it is a typo either A or C, not clear
satellite73:
probably A, hard to tell
rootbeer003:
next
satellite73:
probably D after you do \[\frac{(x+3)\times 2x-(x+5)(x-2)}{(x-3)(x+2)}\]
rootbeer003:
o man
satellite73:
ok, not "probably D" it is D
satellite73:
the 10 at the end gives it away
rootbeer003:
ohok
satellite73:
i am not doing that too much annoying algebra factor and cancel, after you flip the second one or we can cheat
satellite73:
http://www.wolframalpha.com/input/?i=(x%5E2-4x%2B4)(6x%5E4%2B15x%5E3)%2F((12x%5E3%2B30x%5E2)(x%5E2-4))
satellite73:
\[\frac{c(c-2)}{2(c+2)}\]
rootbeer003:
b
satellite73:
B it is
satellite73:
multiplyi top and bottom by \(3x\)
rootbeer003:
b
satellite73:
next
satellite73:
your math teacher must hate you
rootbeer003:
d??
satellite73:
next
satellite73:
\[3(2x+4)=2x(x+2)\] solve for \(x\)
rootbeer003:
c
satellite73:
next
satellite73:
domain is all real numbers except 0, because if you divide by zero you will turn to stone
satellite73:
range is all real numbers except 0 because the numerator is 1
rootbeer003:
o ok
rootbeer003:
c
satellite73:
next
rootbeer003:
a
satellite73:
plug in two, see which one give \(-\frac{9}{16}\) yeah A
satellite73:
they all look kind of the same ...
satellite73:
x cannot be \(-3\) because that would make \(x+3=00\)
satellite73:
and \(f\) cannot be \(-4\)
satellite73:
which one is that?
rootbeer003:
c i think
satellite73:
next
rootbeer003:
c
satellite73:
next
satellite73:
only one has denomimator \(x+4\) pick that one
rootbeer003:
c
satellite73:
next
satellite73:
...
satellite73:
i used a calculator, got \(1.8\)
satellite73:
another C
satellite73:
just pick C every time you will pass
satellite73:
you cannot take the square root of a negative number
satellite73:
yet another C
satellite73:
oh look another C
satellite73:
\[h-6=-20\\ h-6=20\] solve for \(h\)
satellite73:
\[\frac{9}{3-\sqrt2}\times \frac{3+\sqrt2}{3+\sqrt2}\]
satellite73:
the numerator is \(27+9\sqrt2\) and the denominator is \(3^2-2=7\)
satellite73:
oh look another C
satellite73:
oh look, another ...
rootbeer003:
c
satellite73:
oh look, another ...
satellite73:
\[\sqrt{y^2}=y\] pick the one with no \(y\) inside the radical
satellite73:
oh look, another ...
rootbeer003:
c
satellite73:
how many C in a row?
satellite73:
yes
satellite73:
finally a D
rootbeer003:
a
satellite73:
next
satellite73:
the fifth root of thirty two is two two cubed is eight
satellite73:
the fifth root of whatever to the power of five is whatever
satellite73:
4 goes in to 5 one time, with a remainder of 1 so \[\sqrt[4]{x^5}=x\sqrt[4]{x}\]
rootbeer003:
a
rootbeer003:
b
satellite73:
yeah B `
satellite73:
did you save up your homework for like three weeks?
rootbeer003:
ya i did
satellite73:
\[\sqrt{63y^3}=\sqrt{9\times 7\times y^2\times y}=3y\sqrt{7y}\]
rootbeer003:
c
satellite73:
why don't you just fill in C for the rest you will pass
satellite73:
guess what? another ...
satellite73:
who knows?
rootbeer003:
c
rootbeer003:
?
satellite73:
yes of course
satellite73:
guess, i bet you are right
rootbeer003:
idk
rootbeer003:
d
satellite73:
yes you do what is the square root of eight one? what is the square root of one hundred? what is the answer to every question?
satellite73:
no, not D
satellite73:
another C this is getting silly
rootbeer003:
b?
satellite73:
wow good guess yes' B
satellite73:
guess
rootbeer003:
a
satellite73:
no another C
satellite73:
did this still C
satellite73:
\[4i^2=-4\]
rootbeer003:
a
satellite73:
\[42\div 6=7\]
rootbeer003:
a or b?
satellite73:
\[i^{16}=1\]
rootbeer003:
before that
rootbeer003:
a or c
satellite73:
A
satellite73:
like combining like terms
rootbeer003:
a
satellite73:
bingo
rootbeer003:
a
satellite73:
again like combining like terms
rootbeer003:
b
satellite73:
left 3, up 2
satellite73:
yes
satellite73:
same as absolute value 6 units away from the origin
rootbeer003:
b
satellite73:
no
satellite73:
absolute value is always positive
satellite73:
\[\sqrt{2^2+6^2}\]
satellite73:
\[\sqrt{4+36}=\sqrt{40}\]
rootbeer003:
c
satellite73:
no A
satellite73:
square root of 40, not 40
rootbeer003:
the other one was point d
satellite73:
idk i forget
satellite73:
still C
satellite73:
\(-i\) or D
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