rootbeer003:
help
satellite73:
no one's home
rootbeer003:
huh
rootbeer003:
i messaged u???????????
satellite73:
i was on another page, watching some chess
rootbeer003:
can we start?
satellite73:
sure start away
satellite73:
what geometry??
satellite73:
i will guess the y axis, aka \(x=0\)
rootbeer003:
there will only be a few of these
satellite73:
thank god i guess you are just supposed to look at the figure and guess i say \(x=3.5, y=2\) but that is just from my eyeballs. seem reasonable?
rootbeer003:
most definitely!
satellite73:
got me i'd guess option A
satellite73:
\[2\times 5^2-3\] doe
satellite73:
\[(10-7)^3\]
satellite73:
\(y\) intercept is what you get when \(x=0\) i.e. .the constant in this case the constant is four
satellite73:
\[-\frac{b}{2a}=-\frac{6}{-2}=3\]
rootbeer003:
c
satellite73:
yes
satellite73:
\[-\frac{b}{2a}=-\frac{1}{2\times 2}=-\frac{1}{4}\] for this one
satellite73:
the zeros are at \(-5\) and \(2\) and it opens down, making it \[-(x+5)(x-2)\]
rootbeer003:
b
satellite73:
yes that one
satellite73:
vertex is \((2,4)\) so it is either A or B
satellite73:
still the constant, this time 3
satellite73:
first coorinate of the vertex is always \(-\frac{b}{2a}\) which in this case is \[-\frac{2}{2\times (-1)}=1\]
satellite73:
second coordinate is what you get when you replace \(x\) by the first coordinate, in this case \[-1+2+5=6\]
rootbeer003:
b
satellite73:
yes b
satellite73:
not the last one
satellite73:
zeros are at \(1\) and \(-4\) so probably B
rootbeer003:
thats what i thought
rootbeer003:
might wanna get ur glasses for this one
satellite73:
yeah i see' vertex is \((3,6)\) so it looks like \[a(x-3)^2+6\]
rootbeer003:
b?
satellite73:
yeah that is the only one with that vertex
satellite73:
vertex is \((-2,-3)\) so it looks like \[a(x+2)^2-3\]
rootbeer003:
.?
satellite73:
could be B or C plug in 3, see which one gets you 12
satellite73:
think b because \[\frac{3}{5}(3+2)^2-3=\frac{3}{5}\times 25-3=3\times 5-3=12\]
rootbeer003:
how do u type that out so fast
satellite73:
that is why i started with OS, so learn how to type the \[\LaTeX\]
satellite73:
\[\frac{-b\pm\sqrt{b^2-4ac}}{2a}\] with \[a=1, b=1, c=5\]
satellite73:
\[\frac{-1\pm\sqrt{19}i}{2}\]
satellite73:
if the discriminant is negative, there are two complex solutions
rootbeer003:
d
satellite73:
yes D
satellite73:
i don't do word problems
rootbeer003:
i bet google does
satellite73:
\[x(x+5)=310\] is a start
rootbeer003:
b
satellite73:
\[x^2+5x=310\\ x^2+5x-310=0\]
satellite73:
feet per second, \[-16t^2+85t+28\]
satellite73:
\[-16t^2=-30\]
satellite73:
first one DIY
rootbeer003:
-8
satellite73:
second one \[-\frac{b}{2a}\] agaom
satellite73:
yes,. -8
satellite73:
\[-\frac{b}{2a}\] one more time
satellite73:
let me know when you get it
rootbeer003:
idk
satellite73:
\[x^2-4x-5\\ ax^2+bx+c\\ a=?, b=?\]
rootbeer003:
d
satellite73:
\[a=?\\b=?\]
rootbeer003:
c
satellite73:
forget the abcd of the answers\[ax^2+bx+c\\ x^2-4x-5\] what is \(a\) and what is \(b\)??
rootbeer003:
2,-9
satellite73:
lol ok you win
satellite73:
\[-\frac{b}{2a}=2\] and if \(x=2, y=-9\)
satellite73:
the one that crosses the x axis at \(-1\) and at \(4\)
satellite73:
i think that is only one choice
rootbeer003:
a?
satellite73:
yup
satellite73:
the one with vertex \((2,-3)\) that opens up
satellite73:
\[a(x-4)^2+6\]
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