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Mathematics 17 Online
rootbeer003:

help

rootbeer003:

is that it for that question

satellite73:

i forget

satellite73:

what else was there?

rootbeer003:

http://prntscr.com/eki1xl

rootbeer003:

looks good?

satellite73:

the first part is right, the middle part is wrong

rootbeer003:

***

rootbeer003:

Put x as the amount of money at the movie theater , and y as the amount of money at the pet store Then the first equation is 10x+8y=152.50 and the second is 8x+12y=171 10x+8y=152.50 8x+12y=171 I then need to solve Multiply the first equation by −3 and the second equation by (2\) and you get −30x−24y=−457.50 16x+24y=242 10x+8y=152.50 8x+12y=171 you get x=8.25,y=8.75 so $8.25 at the movies, $8.75 at the pet store

rootbeer003:

change it up

satellite73:

Put x as the amount of money at the movie theater , and y as the amount of money at the pet store Then the first equation is 10x+8y=152.50 and the second is 8x+12y=171 10x+8y=152.50 8x+12y=171 I then need to solve

satellite73:

multiply the first equation by \(-3\) and and the second equation by 2 get \[-30x-24y=-457.50\\ 16x+24y=342\] add and get \[-14x=-115.5\] divide by 14 get \[x=8.25\]

satellite73:

substitute \(8.25\) in \[8x+12y=171\] get \[8\times 8.25+12y=171\\ 66+12y=171\\ 12y=105\\ y=8.75\]

satellite73:

there is still another part i think

rootbeer003:

http://prntscr.com/eki3yp

satellite73:

okay still think there s another part to the original question repost it

rootbeer003:

http://prntscr.com/eki4g5

satellite73:

eyah i thiought so work 6 hours at the pet store, needs $168 solve \[8.75\times 6+8.25x=168\]

rootbeer003:

where that go

satellite73:

second part doe

rootbeer003:

ok next question??

satellite73:

\[8.75\times 6+8.25x\eq 168\\ 52.5+8.25x\geq 168\\ 8.25x\geq 115.5\\ x\geq 14\] he needs to work at least 14 hours at the theater

rootbeer003:

umm

satellite73:

next

rootbeer003:

that is not english

rootbeer003:

wait

satellite73:

\[8.75\times 6+8.25x\geq 168\\ 52.5+8.25x\geq 168\\ 8.25x\geq 115.5\\ x\geq 14\]

rootbeer003:

wheres that go

rootbeer003:

end?

satellite73:

yes, goes at the end

rootbeer003:

http://prntscr.com/eki6q2

satellite73:

\[f(x)=x^2-2x-3=(x-3)(x+1)\] to ind the x intercepts \[(x-3)(x+1)=0\\ x=3, x=-1\]

satellite73:

to find the y intercept \[f(0)=-3\] y intercept is \((0,-3)\)

satellite73:

first coordinate of the vertex is \[x=-\frac{b}{2a}=-\frac{-2}{2\times 1}=1\] then \[f(1)=1^2-2-3=-4\] vertex it \((1,-4)\)

rootbeer003:

thts all?

satellite73:

make sure to plot the points \((1,-4), (0,-3), (-1,0), (3,0)\)

rootbeer003:

http://prntscr.com/eki8jx

satellite73:

ooooookay

rootbeer003:

look s good?

satellite73:

yes, good an ugly

rootbeer003:

like me!

rootbeer003:

ok thank you and have a good day

satellite73:

lol, like blondie really? done/

satellite73:

go do something fun, i'll see you later

rootbeer003:

byee

satellite73:

byee

rootbeer003:

wait

rootbeer003:

@satellite73

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