help
is that it for that question
i forget
what else was there?
looks good?
the first part is right, the middle part is wrong
***
Put x as the amount of money at the movie theater , and y as the amount of money at the pet store Then the first equation is 10x+8y=152.50 and the second is 8x+12y=171 10x+8y=152.50 8x+12y=171 I then need to solve Multiply the first equation by −3 and the second equation by (2\) and you get −30x−24y=−457.50 16x+24y=242 10x+8y=152.50 8x+12y=171 you get x=8.25,y=8.75 so $8.25 at the movies, $8.75 at the pet store
change it up
Put x as the amount of money at the movie theater , and y as the amount of money at the pet store Then the first equation is 10x+8y=152.50 and the second is 8x+12y=171 10x+8y=152.50 8x+12y=171 I then need to solve
multiply the first equation by \(-3\) and and the second equation by 2 get \[-30x-24y=-457.50\\ 16x+24y=342\] add and get \[-14x=-115.5\] divide by 14 get \[x=8.25\]
substitute \(8.25\) in \[8x+12y=171\] get \[8\times 8.25+12y=171\\ 66+12y=171\\ 12y=105\\ y=8.75\]
there is still another part i think
okay still think there s another part to the original question repost it
eyah i thiought so work 6 hours at the pet store, needs $168 solve \[8.75\times 6+8.25x=168\]
where that go
second part doe
ok next question??
\[8.75\times 6+8.25x\eq 168\\ 52.5+8.25x\geq 168\\ 8.25x\geq 115.5\\ x\geq 14\] he needs to work at least 14 hours at the theater
umm
next
that is not english
wait
\[8.75\times 6+8.25x\geq 168\\ 52.5+8.25x\geq 168\\ 8.25x\geq 115.5\\ x\geq 14\]
wheres that go
end?
yes, goes at the end
\[f(x)=x^2-2x-3=(x-3)(x+1)\] to ind the x intercepts \[(x-3)(x+1)=0\\ x=3, x=-1\]
to find the y intercept \[f(0)=-3\] y intercept is \((0,-3)\)
first coordinate of the vertex is \[x=-\frac{b}{2a}=-\frac{-2}{2\times 1}=1\] then \[f(1)=1^2-2-3=-4\] vertex it \((1,-4)\)
thts all?
make sure to plot the points \((1,-4), (0,-3), (-1,0), (3,0)\)
ooooookay
look s good?
yes, good an ugly
like me!
ok thank you and have a good day
lol, like blondie really? done/
go do something fun, i'll see you later
byee
byee
wait
@satellite73
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