Can someone help me
@alones
@Nnesha
distribute 2nd parentheses by -1 and then combine like terms add the coefficient with the variable i
@satellite73 can you help please
@satellite73 oh lol I just opened peer answer and saw that you replied
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i am here
\[(3-8i)-(6+2i)=3-8i-6-2i=-3-10i\]
Hi =)
OKay so would that be for step 1?
distribute the minus sign
it would be the same fo r\[(3-8x)-(6+2x)\]
just with an \(i\) instead of an \(x\) like combining like terms remove the parentheses using the distributive property first, then combine like terms
Okay so would all of this be step 1?
\[(3-8i)-(6+2i)\] step one, distribute the minus sign \[3-8i-6-2i\]
Play and then step 2
Okay**
maybe you can arrange the like terms next to each other, not sure if that is a step or not \[3-6-8i-2i\]
or just combine the like terms \[-3-10i\]
ok now i see it says "rewrite as an addition problem" we can do that too
\[(3-8i)-(6+2i)=(3-8i)+(-6-2i)\]
it is silly, but you can write it like that then second step is still to combine like terms, and you still get \[-3-10i\]
Okay so step one is (3-8i)-(6+2i)=(3-8i)+(-6-2i)
and then step two -3-10i
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