Which pair of events are independent of each other? selecting an ace from a deck of cards, and then drawing another ace without replacing the first getting an even number on the first and second roll of the die drawing a red paperclip from a bag of paperclips, and then drawing another red paperclip without replacing the first drawing a ball from a bag, and then drawing another ball without replacing the first
@Hero
@Falconmaster, do you have any ideas about which option might be correct?
A?
Why A?
because he did not put the card back
What happens if you don't put the card back?
What happens to the deck?
ihe wont draw the card again
Right, but let's say you were keeping track of the probability of drawing an ace from the deck. The probability of drawing the first ace is 4/52. But you don't put the card back before drawing the second ace. What do you think happens to the deck before drawing the second ace?
Will the probability of drawing an ace be the same when drawing the second ace as it was when drawing the first ace?
The chances decrees to 3/52
Yeah, but if you remove the 1st ace, how many cards are now in the deck?
51
Exactly, so does not the probability of drawing the second ace "DEPEND ON" whether or not the ace was replaced?
yes i think
So what conclusion can we draw about "not replacing" things when keeping track of the probability of an event?
That the odds ill stay the same?
*will
Will it really? If we don't replace the ace on the first draw, what happens to the probability on the second draw? Is the probability of drawing the second card the same as the probability of drawing the 1st card?
no?
Exactly, so I ask you once again, what conclusion can we come to about "not replacing" things when tracking the probability of an event?
that it will be dependant
Precisely. The probability of the second event will depend on the 1st event. So look at your answer choices again and see how many of them involve "not replacing" things.
You're welcome.
Okay thanks.
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