Question

URGENT HELP ON THIS

Answer 1

Find F(2)

Answer 2

@zarkam21

Answer 3

Hi please help me please

Answer 4

@zarkam21 I gave you a huge hint on what to do.

Answer 5

would I do F(2)= x^4-2x^3+3x^2-10x+3?

Answer 6

F(2) = 2^4 - 2(2)^3 = 3(2)^2 - 10(2) + 3

Answer 7

I got 0?

Answer 8

F(2) = 16 - 16 + 12 - 20 + 3

Answer 9

-5/2?

Answer 10

@Hero

Answer 11

Explain how you got -5/2

Answer 12

Well I used mathway.com

Answer 13

There is no way to get -5/2 if you have nothing but whole numbers to evaluate

Answer 14

Ill help ya!

Answer 15

11?

Answer 16

@Hero

Answer 17

-7

Answer 18

@Hero

Answer 19

That is closer to the answer but not quite.

Answer 20

-5

Answer 21

Correct finally. Congrats

Answer 22

Okay so is that step one to the problem

Answer 23

Actually, that was part II. Part I was to identify the "a".

Answer 24

Hopefully you know what "a" is at this point.

Answer 25

2?

Answer 26

?

Answer 27

@Hero

Answer 28

Yes, a = 2 in this case. Are you familiar with the remainder theorem?

Answer 29

umm I think so

Answer 30

Can you describe what the remainder theorem is in your own words?

Answer 31

It factors F(x)

Answer 32

The remainder theorem is the assertion that \(P(c)\) is the remainder when polynomial \(P(x)\) is divided by \(x – c\).

What is implied here is that \((x - c)\) divides \(P(c)\) evenly only if the remainder is zero.
In other words, \((x - c)\) is a factor of \(P(x)\) if and only if \(P(c) = 0\).

Answer 33

so only if it ends up in zero it applies

Answer 34

What I wrote above, is the explanation for Part III.

Answer 35

Oh okay thank you